Correct question is;
A bag contains 10 counters. 6 of them are white. A counter is taken at random and not replaced. A second counter is taken out of the bag at random. Calculate the probability that only one of the two counters are white
Answer:
probability that only one of the two counters is white = 8/15
Step-by-step explanation:
To solve this question, first of all, let's look at probability we would have to either draw two white counters or two non-white counters (4/10 * 3/9).
Probability(draw 2 white counters) = (6/10 × 5/9) = 30/90 = 1/3
Probability(draw 2 non-white counters) = (4/10 × 3/9) = 2/15
Now, In all other cases, we'll draw exactly one white and one non-white counter, so the odds of this would be;
P(one white counter and one non-white counter) = 1 - [1/3 + 2/15)
= 1 - 7/15 = 8/15
Answer:
QS=SR ( being PS median of triangle PQR,psㅗQR)
<QPS=<SPR (Median PS bisects the angle P)
HOPE THIS WILL HELP YOU...!
Question 1:
For this case we must rewrite the following equation:
If we add 3x to both sides of the equation we have:
Thus, we have that an equivalent expression is option C.
Answer:
Option C
Question 2:
For this case we must solve the following equation:
Subtracting 5 from both sides of the equation we have:
Dividing between -5 on both sides of the equation we have:
Answer:
Option B
Answer:
Step-by-step explanation:
The two have a total of 5+2 = 7 "ratio units" so have a total of 140 cars.
can you mark me as brainliest?
| x - 8| = 3
x - 8 = 3 - (x - 8) = 3
x = 3 + 8 -x + 8 = 3
x = 11 -x = 3 - 8
-x = - 5
x = 5
Minimum : 5% Maximum : 11% if u need them added it is 16%
