You add each number by 6n - fourth choice. I am not sure if this is the right answer.
Their distance differs by 15 miles for each hour of travel time. Thus, the travel time of interest is
.. (180 -144) miles/(15 miles/hour) = 2.4 hour
The red car's speed is 180 mi/(2.4 h) = 75 mi/h.
The blue car's speed is 144 mi/(2.4 h) = 60 mi/h.
What is the interquartile range of this data set? 2,5,9,11,18,30,42,55,58,73,81
Tcecarenko [31]
Answer:
I think it's 49 I'm sry if I'm wrong hope you luck
Step-by-step explanation:
the division of the quarter is 6x
Answer: First option.
Step-by-step explanation:
The complete exercise is attached.
In order to solve this exercise, it is necessary to remember the following property:
The Multiplication property of Equality states that:

In this case, the equation that Jada had is the folllowing:

Jada needed to solve for the variable "x" in order to find its value.
The correct procedure to solve for for "x" is to multiply both sides of the equation by 108. Then, you get:

As you can notice in the picture, Jada did not multiply both sides of the equation by 108, but multiplied the left side by
<em> </em>and the right side by
.
Therefore,you can conclude that Jada should have multiplied both sides of the equation by 108.