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2 years ago

Please help asapppppp

Mathematics

1 answer:

solong [7]2 years ago

3 0

Answer:

45 degree

Step-by-step explanation:

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Evaluate 23x + 4y when x=20 and y=23

never [62]

Answer:

552

Step-by-step explanation:

23x + 4y when x=20 and y=23

if x=20 and y=23 all you have to do is replace the numbers and solve

23(20) + 4(23)

Multiply 23*20 which is equal to 460

Then you multiply 4*23 which is equal to 92

The problem is now 460 + 92

add it, and you get 552.

Hope this helps!!

-Ketifa

3 0

3 years ago

What is the answer to this question?

harina [27]

Answer:

f(g(0) )= -1

Step-by-step explanation:

Find g(0) = -1

Then find f(-1) = 1

f(g(0) )= -1

4 0

2 years ago

A. The following events are mutually exclusive: Living in California and watching American Idol. True or False b. The number of

BlackZzzverrR [31]

Answer:

a) False. Because you can live in California AND watch American Idol at the same time

b) True. Because the number of patients is a whole number, like 1, 2 or 3. There is no 1.5 patient

c) False. The actual probability should become closer to the theoretical probablity

d) True

3 0

3 years ago

1. Find the distance between the points (1, 2) and (-2,-2).

alexandr1967 [171]

Answer:

Step-by-step explanation:

5 0

3 years ago

In the expansion of (3a + 4b)8, which of the following are possible variable terms? Explain your reasoning. a2b3; a5b3; ab8; b8;

Fiesta28 [93]

We have to find the expansion of $(3a+4b)^{8}$

We will use binomial expansion to expand the given expression, which states that the expression $(a+b)^{n}$ is expanded as :

$(a+b)^{n}=^{n}C_{0}a^{n}+^{n}C_{1}a^{n-1}b+^{n}C_{2}a^{n-2}b^{2}+........^{n}C_{n}b^{n}$

Now expanding $(3a+4b)^{8}$ we get,

$(3a+4b)^{8}=^{8}C_{0}(3a)^{8}+^{8}C_{1}(3a)^{7}(4b)+^{8}C_{2}(3a)^{6}(4b)^{2}+^{8}C_{3}(3a)^{5}(4b)^{3}+^{8}C_{4}(3a)^{4}(4b)^{4}+^{8}C_{5}(3a)^{3}(4b)^{5}+^{8}C_{6}(3a)^{2}(4b)^{6}+^{8}C_{7}(3a)(4b)^{7}+^{8}C_{8}(4b)^{8}$

$(3a+4b)^{8}=^{8}C_{0}(3)^{8}a^{8}+^{8}C_{1}(3)^{7}(4)(a^{7}b)+^{8}C_{2}(3)^{6}(4)^{2}(a^{6}b^{2})+^{8}C_{3}(3)^{5}(4)^{3}(a^{5}b^{3})+^{8}C_{4}(3)^{4}(4)^{4}(a^{4}b^{4})+^{8}C_{5}(3)^{3}(4)^{5}(a^{3}b^{5})+^{8}C_{6}(3)^{2}(4)^{6}(a^{2}b^{6})+^{8}C_{7}(3)(4)^{7}(ab^{7})+^{8}C_{8}(4)^{8}(b^{8})$

So, the variables are $a^{5}b^{3}$ , $b^{8}$ , $a^{4}b^{4}$ , $a^{8} , [tex] ab^{7}$

5 0

2 years ago