The sun is not a living thing. It is made up of gases, such as hydrogen and helium, rather than living cells, which are present in all forms of life
When stimulated by the hormone known as FSH (Follicle-stimulating hormone).
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The correct answer is: [B]: "decreased" .
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<u>Note</u>:
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In a graph of "coal reserves in the United States" vs. "time" ;
→ the "time" is the "independent variable" that belongs on the "x-axis" .
→ The quantity or amount of "coal reserves in the United States" is the "dependent variable" that belongs on the "y-axis" .
If the graph "slopes downward" ; this would indicate a "decrease" in the amount/quantity of "coal reserves" over "time" .
→ As the value of "x" increases — "time" increases — and; as "x" increases, the value of "y" {the amount/quantity of "coal reserves"} decreases.
→ This would be represented by a "downward sloping" graph;
→ and, among the answer choices given, could indicate that coal production:
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→ "decreased" ;
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→ which is: Answer choice: [B]: "decreased" .
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Answer:
6,25%
Explanation:
Considering that the couple has a trait of sickle cell anemia, we know that both are heterozygous for the disease (Aa) and therefore can have children with the following genotypes:
Parents: Aa X Aa
Children: AA(A x A), Aa(A x a), Aa (a x A) and aa(a x a)
Knowing that sickle cell anemia only occurs in homozygous individuals, the probability for children to have the disease according to each crossing is:
A x A = 1/4 = 25%
A x a = 1/4 = 25%
a x A = 1/4 = 25%
a x a = 1/4 = 25%
The probability of forming each homozygous child (aa) is 1/4 or 25%. Since they are two children, the probability of both having sickle cell anemia is calculated by multiplying the probability of each, so:
1/4 × 1/4 = 1/16 = 0.0625 = 6.25%
It is concluded that the probability of a heterozygous couple for sickle cell anemia to have two children with the disease is 6.25%.
The classes of chordata which are warm-blooded are birds and mammals.
Explanation:
Warm-blooded animals are those which can maintain their body temperature at a constant.
These classes of chordates balance their internal body temperature with that of the outer environment. When the outer environment is cold, they increase their internal temperature by producing more heat; and when it is hot outside they reduce their internal temperature by cooling themselves.
The food consumed by a warm-blooded animal fuels to maintain a constant body temperature and hence they require more food.
Warm blooded animals cool themselves with the help of sweat glands.
The skin and other parts like fur in birds help to keep the animals warm during winter. Birds also shed their fur in hot season to keep them light. Birds migrate to warm regions during winter.
These animals have high stamina and energy to survive environmental changes. They maintain their temperature through endothermy, homeothermy or tachymetabolism.
Whale living in water is the fish which is also warm blooded because it is a mammal.
