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3 years ago

HELP PLS ASAP! I BEG U! PLS! PICTURE ADDED! Complete the sentences below for the numbers 16

Mathematics

1 answer:

Julli [10]3 years ago

5 0

Answer:

number to the right of 0 is 16

the number that is the least is -15

-15 is farther from 0 than -9 is

Step-by-step explanation:

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Describe the leading coefficient,

Orlov [11]

It’s Negative below the lines the touching points do not meet

8 0

3 years ago

Red Top Cab Company receives multiple complaints per day about driver behavior. Over 9 days the owner recorded the number of cal

zysi [14]

Answer:

upper control limit = 13.34

Step-by-step explanation:

The c-chart is used to check the change in the number of recorded calls per day

First find out the center line

c = sum of recorded calls/number of days

c = (3 + 0 + 8 + 9 + 6 + 7 + 4 + 9 + 8)/9

c = 54/9

c = 6

The upper control limit for 3σ is

upper control limit = c + 3√c

upper control limit = 6 + 3√6

upper control limit = 13.34

Therefore, the upper control limit for the 3-sigma c-chart is 13.34.

8 0

4 years ago

Someone help me!

Delvig [45]

11/8 = x / 3

cross multiply

8x = 11 * 3

8x = 33

x =33/8

x = 4.125

x = 4.1 (round to nearest tenth)

Answer

B: 4.1 ft

6 0

3 years ago

Help ! With step by step solution

nirvana33 [79]

Answer:

the correct answer is C

Step-by-step explanation:

first step you change the x and y powers to the square root(showing in the pic).

second the number outside of the parenthesis times the numbers inside the parenthesis and then you just figure it out how it works...

7 0

3 years ago

Kaden works 5 days. The median number of hours he works is 3. The mean number of hours he works is 4.

alisha [4.7K]

Answer:

(a) 1, 2, 3, 6, 8

Step-by-step explanation:

Given

$Median = 3$

$Mean = 4$

Required

The sequence of hours worked each day

<em>See attachment for options</em>

From the question, we understand that:

$Median = 3$

This means that, the middle number is 3 (when sorted)

So, we can conclude that (b) and (c) cannot be true because their middle numbers are 6 and 5 respectively

Next, is to determine the mean of (a) and (d)

The mean of a data is calculated as:

$\bar x = \frac{\sum x}{n}$

So, we have:

(a)

$\bar x = \frac{1+ 2+ 3+ 6+ 8}{5}$

$\bar x = \frac{20}{5}$

$\bar x = 4$

(d)

$\bar x = \frac{1+ 2+ 3+ 4+ 5}{5}$

$\bar x = \frac{15}{5}$

$\bar x = 3$

Option (a) is true, because it has:

$Median = 3$

$Mean = 4$

7 0

3 years ago