All categories

2 years ago

Hi. I need help wih this question (see image). Please show workings.

Mathematics

1 answer:

Kipish [7]2 years ago

4 0

Answer:

$\frac{dy}{dx}$ = 12x³ - 6x² - 7

Step-by-step explanation:

Differentiate each term using the power rule

$\frac{d}{dx}$ (a $x^{n}$ ) = na $x^{n-1}$

Given

y = 3 $x^{4}$ - 2x³ - 7x + 5, then

$\frac{dy}{dx}$ = 4.3 $x^{4-1}$ - 3.2 $x^{3-1}$ - 7 $x^{1-1}$ + 0

= 12x³ - 6x² - 7

You might be interested in

Find the limit as x approaches 0 for cos(2x) / x

zhenek [66]

We are asked to determine the limits of the function cos(2x) / x as x approaches to zero. In this case, we first substitute zero to x resulting to 1/0. A number, any number divided by zero is always equal to infinity, Hence there are no limits to this function.

5 0

3 years ago

Which is an asymptofe of the graph the function y=cot(x-2π/3)

Shalnov [3]

Hello.

C) x=4π/3

The variable x in the cotangent argument has a unit coefficient, so the period is π, just as it is in the parent function cot(x).

Can you graph y = cot(x)? By subtracting the constant π/6 from the argument, that graph is translated to the right by π/6. Just as with cot(x), it is decreasing everywhere.

Have a nice day

5 0

3 years ago

Consider an experiment with sample space S 5 50, 1, 2, 3, 4, 5, 6, 7, 8, 96 and the events A 5 {0, 2, 4, 6, 8} B 5 {1, 3, 5, 7,

Brut [27]

Answer with Step-by-step explanation:

S={0,1,2,3,4,5,6,7,8,9}

A={0,2,4,6,8}

B={1,3,5,7,9}

C={0,1,2,3,4}

D={5,6,7,8,9}

a.A'=S-A

A'={0,1,2,3,4,5,6,7,8,9}-{0,2,4,6,8}

A'={1,3,5,7,9}

b.C'=S-C

C'={0,1,2,3,4,5,6,7,8,9}-{0,1,2,3,4}

C'={5,6,7,8,9}

c.D'=S-D

D'={0,1,2,3,4,5,6,7,8,9}-{5,6,7,8,9}

D'={0,1,2,3,4}

d. $A\cup B=$ {0,2,4,6,8} $\cup$ {1,3,5,7,9}

$A\cup B=$ {0,1,2,3,4,5,6,7,8,9}=S

e. $A\cup C$ ={0,2,4,6,8} $\cup$ {0,1,2,3,4}

$A\cup C$ ={0,1,2,3,4,6,8}

f. $A\cup D$ ={0,2,4,6,8} $\cup$ {5,6,7,8,9}

$A\cup D$ ={0,2,4,5,6,7,8,9}

8 0

3 years ago

Please help, i have no idea how to do this

notsponge [240]

Answer:

8 square units

Step-by-step explanation:

The figure is a trapezoid. The area of it is given by the formula ...

A = (1/2)(b1 +b2)h

where b1 and b2 are the lengths of the parallel bases and h is the distance between them.

Your figure shows the base lengths to be 5 and 3, and their separation to be 2. Filling the numbers in the formula, we have ...

A = (1/2)(5 +3)(2) = (1/2)(8)(2) = 4·2 = 8

The area of the figure is 8 square units.

_____

The right-pointing arrows on the horizontal lines identify those lines as being parallel. The right-angle indicator and the 2 next to the dotted line indicate the perpendicular distance between the parallel lines is 2 units.

4 0

3 years ago

If anyone can check my work for me that would be greatly appreciated I'm having trouble.

krek1111 [17]

The answer is -13. Solution: = |-4b - 8| + |-1 - b^2| + 2b^3 = |-4(-2) - 8| + |-1 - -2^2| + 2(-2)^3 = |8-8| + |-1+4| + 2(-8) = |0| + |3| + (-16) = -13

8 0

2 years ago

Hi. I need help wih this question (see image). Please show workings.​

Hi. I need help wih this question (see image). Please show workings.