Given 2x+4y=12 what is the x and y int

What is the degree of (3x^2-3)(3x^2+3)

r-ruslan [8.4K]

Answer:

9x^4+3x^2 -6

Step-by-step explanation:

(3x^2-2)(3x^2+3)

expand to remove the bracket

9x^4 + 9x^2 -6x^2 - 6

9x^4 + 3x^2- 6

5 0

2 years ago

What is the asymptote of this function? A) x=3 B) y=3 C) x=4 D) y=4

max2010maxim [7]

Answer:

b

Step-by-step explanation

look at the way the way the line curves and cross over into the positive across the dotted line. the curw = y

5 0

2 years ago

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A vacant lot is being converted into a community garden. The garden and and a walkway around its perimeter have an area of 460 s

mariarad [96]

Answer:

The width of the walkway is 4 feet.

Step-by-step explanation:

The garden and a walkway around its perimeter have an area of 460 square feet.

The length of the garden = 15 feet

The width of the garden = 12 feet

Assuming that walkway is of uniform width, we can solve the following equation.

$(12+2x)\times(15+2x)= 460$

Expanding this we get;

$4x^{2}+54x+180=460$

$=> 4x^{2}+54x-280=0$

We will solve this using quadratic equation formula:

$x=\frac{-b\pm \sqrt{b^{2} -4ac} }{2a}$

Here a = 4 , b = 54 , c = -280

We get the roots as x = 4 and x = $-\frac{35}{2}$

Neglecting the negative value, we will take x = 4 feet.

Hence, the width of the walkway is 4 feet.

5 0

2 years ago

If P(A)=0.43 and P(B)=0.09, find P(A and B). Round your answer to the nearest hundredth.

AleksAgata [21]

Answer:

0.04 to the nearest hundredth.

Step-by-step explanation:

P(A and B)

= P(A ∩ B

= P(A) * P(B)

= 0.43 * 0.09

= 0.0387.

=

5 0

2 years ago

You want to install a 2 yd wide walk around a circular swimming pool. The diameter of the pool is 23 yd. What is the area of the

GrogVix [38]

Answer:

157 square yards.

Step-by-step explanation:

Given:

Width of walk around a circular swimming pool = 2 yard

The diameter of the pool = 23 yard

Question asked:

What is the area of the walk ?

Solution:

To find area of walk, we will first calculate area of the pool and then combined area of pool and walk then after we will subtract the area of pool from combined area.

The diameter of the pool = 23 yard

Radius of the pool = $\frac{diameter }{2}=\frac{23}{2} =11.5\ yard$

$Area\ of\ circle=\pi r^{2}$

$=3.14\times(11.5)^{2} \\=3.14\times11.5\times11.5=415.265\ square\ yard$

As width of walk around a circular swimming pool is 2 yard :

New radius will be = 11.5 + 2 = 13.5 yard

$Combined\ area =\pi r^{2} \\$

$=3.14\times13.5\times13.5=572.265\ square\ yard$

Now, area of the walk = Combined area of pool and walk - Area of the pool

= 572.265 - 415.265

= 157 square yards

Therefore, area of the walk is 157 square yards.

4 0

2 years ago

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