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3 years ago

PLEASE ANSWER ASAP !!!!

Mathematics

2 answers:

Flauer [41]3 years ago

6 0

There is a trick to this. Remember that it’s run (x) over jump (y).

So in this instance, you find where the line connects with the corner of a blue square. (-1, -3) is one. Now find the second one. Which is (3, 4)

Now find the space between those two corners. 7/4

Radda [10]3 years ago

3 0

Answer:

The awnser is 7/4!!!!!!!!

You might be interested in

Read the following statement. If a number is divisible by 2,then it is even what is the inverse of this statement?

Lapatulllka [165]

Answer:

If it is an even number, then it is divisible by 2

Step-by-step explanation:

You flip the order of statements. One statement is "a number is divisible by 2", the other is "it is even" is the other.

7 0

3 years ago

Luda [366]

Answer:

a) H0: There is no association between level of education and TV station preference (Independence)

H1: There is association between level of education and TV station preference (No independence)

b) $\chi^2 = \frac{(15-10)^2}{10}+\frac{(15-20)^2}{20}+\frac{(10-10)^2}{10}+\frac{(5-10)^2}{10}+\frac{(25-10)^2}{10}+\frac{(10-20)^2}{20} =33.75$

c) $\chi^2_{crit}=5.991$

d) Since the p value is lower than the significance level we enough evidence to reject the null hypothesis at 5% of significance, and we can conclude that we have dependence between the two variables analyzed.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

High school Some College Bachelor or higher Total

Public Broadcasting 15 15 10 40

Commercial stations 5 25 10 40

Total 20 40 20 80

We need to conduct a chi square test in order to check the following hypothesis:

Part a

H0: There is no association between level of education and TV station preference (Independence)

H1: There is association between level of education and TV station preference (No independence)

The level os significance assumed for this case is $\alpha=0.05$

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

Part b

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{total col * total row}{grand total}$

And the calculations are given by:

$E_{1} =\frac{20*40}{80}=10$

$E_{2} =\frac{40*40}{80}=20$

$E_{3} =\frac{20*40}{80}=10$

$E_{4} =\frac{20*40}{80}=10$

$E_{5} =\frac{40*40}{80}=20$

$E_{6} =\frac{20*40}{80}=10$

And the expected values are given by:

High school Some College Bachelor or higher Total

Public Broadcasting 10 20 10 40

Commercial stations 10 10 20 40

Total 20 30 30 80

Part b

And now we can calculate the statistic:

$\chi^2 = \frac{(15-10)^2}{10}+\frac{(15-20)^2}{20}+\frac{(10-10)^2}{10}+\frac{(5-10)^2}{10}+\frac{(25-10)^2}{10}+\frac{(10-20)^2}{20} =33.75$

Now we can calculate the degrees of freedom for the statistic given by:

$df=(rows-1)(cols-1)=(2-1)(3-1)=2$

Part c

In order to find the critical value we need to look on the right tail of the chi square distribution with 2 degrees of freedom a value that accumulates 0.05 of the area. And this value is $\chi^2_{crit}=5.991$

Part d

And we can calculate the p value given by:

$p_v = P(\chi^2_{3} >33.75)=2.23x10^{-7}$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(33.75,2,TRUE)"

Since the p value is lower than the significance level we enough evidence to reject the null hypothesis at 5% of significance, and we can conclude that we have dependence between the two variables analyzed.

7 0

4 years ago

Solve pls brainliest

diamong [38]

Answer:

3/8 = 9/24

1/3 = 8/24

3/8 > 1/3

Step-by-step explanation:

3/8 = 9/24 (multiply both numerator and denominator by 3)

1/3 = 8/24 (multiply both numerator and denominator by 8)

9/24 > 8/24

6 0

2 years ago

There are several marbles in a bag: two red, four green, one blue, and five yellow. What is the probability of randomly drawing

GREYUIT [131]

Answer:

The probability is 5/36

Step-by-step explanation:

The total number of marbles is 2 + 4 + 1 + 5 = 12 marbles

The probability of randomly drawing a green marble would be

number of green marble/total number of marbles = 4/12 = 1/3

Now since we are replacing the total number of marbles stays the same

so, the probability of drawing a yellow marble now will be ;

number of yellow marbles/total number of marbles = 5/12

So the total probability we are having here would be; 1/3 * 5/12 = 5/36

5 0

3 years ago

Which of the following proportions is true?<br> 4/16=2/14 15/20=24/36 12/15=47/50 16/36=12/27

KengaRu [80]

The correct proportion is 16/36=12/27

4 0

3 years ago