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3 years ago

PLEASE ANSWER ASAP !!!!

Mathematics

2 answers:

Flauer [41]3 years ago

6 0

There is a trick to this. Remember that it’s run (x) over jump (y).

So in this instance, you find where the line connects with the corner of a blue square. (-1, -3) is one. Now find the second one. Which is (3, 4)

Now find the space between those two corners. 7/4

Radda [10]3 years ago

3 0

Answer:

The awnser is 7/4!!!!!!!!

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What is the volume of this triangular prism? 313.6cm3 506.8cm3 5,676.16cm3 11,352.32cm3

lyudmila [28]

The question is incomplete. Here is the complete question:

What is the volume of this triangular prism?

Base length = 22.4 cm

Height = 18.1 cm

Length = 28 cm

A) 313.6 cm3

B) 506.8 cm3

C) 5,676.16 cm3

D) 11,352.32 cm3

Answer:

$V=5,676.16\ cm^3$

Step-by-step explanation:

Given:

The base of the prism is triangular with base length equal to 22.4 cm and height 18.1 cm. The length of the prism is 28 cm.

The volume of a triangular prism is defined by the formula:

$V=(Area\ of\ base)\times (length)$

Here, the base is triangular and the area of a triangle is:

$A=\frac{1}{2}base \times height$

Therefore, the volume of the triangular prism is given as:

$V=\frac{1}{2}(base\times height\times length)$

Now, plug in the given values and solve for the volume 'V'.

$V=\frac{1}{2}(22.4\ cm\times 18.1\ cm\times 28\ cm)\\\\V=\frac{1}{2}(11,352.32\ cm^3)\\\\V=5,676.16\ cm^3$

Therefore, the correct answer is the third option.

$V=5,676.16\ cm^3$

7 0

3 years ago

Read 2 more answers

Jen Butler has been pricing Speed-Pass train fares for a group trip to New York. Three adults and four children must pay $ 79.

xxMikexx [17]

<u>Answer:</u>

Price of the adult's ticket = $13

Price of a child's ticket = $ 10

<u>Step-by-step explanation:</u>

Given:

Cost of train fares for Three adults and four children = $79

Cost of train fares Two adults and three children = $ 56

To Find:

Price of the adult's ticket and the price of a child's ticket =?

Solution:

Let the cost of one adult's ticket be x and

Let the cost of one child's ticket be y

Then

Three adults and four children must pay $ 79 be

3x + 4y = 79-----------------------------------------------(1)

Two adults and three children must pay $56

2x + 3y = 56----------------------------------------------(2)

multiply eq(1) by 2, we get

6x + 8y = 158----------------------(3)

multiply eq(2) by 3, we get

6x + 9y = 168----------------------(4)

Subracting (3) from (4)

6x + 9y = 168

6x + 8y = 158

(-) (-) (-)

------------------------------

0x + y = 10

------------------------------

y=10

Now substitute the value of y in eq (1) to get the value of x

3x + 4(10)= 79

3x + 40 = 79

3x = 79 - 40

3x = 39

x = $\frac{39}{3}$

x= 13

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Answer:

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9+2x≤27

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x≤9

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