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castortr0y [4]
3 years ago
15

Which axis did the point (-7, -6) reflect over if it ended up at (7, -6)? *

Mathematics
1 answer:
Dvinal [7]3 years ago
4 0

Answer:

x axis

Step-by-step explanation:

it will be higher than the first point but not move left or right so by visualising it would be reflected by the x-axis

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Find the value of i^9
Tcecarenko [31]

Answer:

The answer is i (i^9)

Step-by-step explanation:

6 0
3 years ago
Simplify 14 to the power of 15 over 14 to the power of 5
BartSMP [9]

Answer:

1. Use Quotient Rule

{14}^{15-5}

2. Simplify  

{14}^{10}

3 Simplify.

289254654976289254654976

Step-by-step explanation:

6 0
3 years ago
X - (-3) is the same as x (-3). true false
liq [111]
False

x-1(-3)=x+(-3)
x+3=x-3
3=-3
false

NO
7 0
3 years ago
Read 2 more answers
A- CE=CD <br> B- CE = CA <br> C- BF=DF <br> D- DF=EF<br><br> please help!!
Oksana_A [137]

The perpendicular bisector theorem gives the statements that ensures

that \overleftrightarrow{FG} and \overleftrightarrow{AB} are perpendicular.

The two statements if true that guarantee  \overleftrightarrow{FG} is perpendicular to line \overleftrightarrow{AB} are;

  • \overline{CE} = \overline{CD}
  • \overline{DF} = \overline{EF}

Reasons:

The given diagram is the construction of the line \mathbf{\overleftrightarrow{FG}} perpendicular to line \mathbf{\overleftrightarrow{AB}}.

Required:

The two statements that guarantee that  \overleftrightarrow{FG} is perpendicular to line \overleftrightarrow{AB}.

Solution:

From the point <em>C</em> arcs <em>E</em> and <em>D</em> are drawn to cross line \overleftrightarrow{AB}, therefore;

\overline{CE} = \mathbf{\overline{CD}} arcs drawn from the same radius.

\overleftrightarrow{FG} is perpendicular to line \overleftrightarrow{AB}, given.

Therefore;

\overline{DF} = \overline{EF}  by perpendicular bisector theorem.

Learn more about the perpendicular bisector theorem here:

brainly.com/question/11357763

7 0
3 years ago
The center of a circle is (4, 6), and an endpoint of a diameter is (2, 5). What is the other endpoint of the diameter?
valentinak56 [21]
Consider this option:
1. if the point (4;6) is the centre of the circle and the point (2;5) is the first endpoint of its diameter, then point (4;6) is the middle point of the diameter (it means that is the middle between the 1st and the 2d endpoints of diameter).
2. using the property described above:
for x of the 2d endpoint of the diameter: x=4*2-2=6;
for y of the 2d endpoint of the diameter: y=6*2-5=7.

answer: (6;7)
3 0
3 years ago
Read 2 more answers
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