The altitude of a triangle forms a perpendicular line. False True

I NEED HELP RN PLEASEEEE ITS AN EMERGENCY!!

strojnjashka [21]

Answer:

The answer is C) $12\sqrt{2}$ .

Step-by-step explanation:

For a real number $a$ ,

$\sqrt{a} \cdot \sqrt{a} = a$ .

In other words, multiplying a square root by itself gets rid of the square root.

How does this rule apply here?

$24 = 2\times 12$ .

Similarly,

$\sqrt{24} = \sqrt{2}\times \sqrt{12}$ .

That is:

$\begin{aligned}\sqrt{24}\times \sqrt{12} &= (\sqrt{2}\times \sqrt{12}) \times \sqrt{12}\\&=\sqrt{2}\times (\sqrt{12}\times \sqrt{12}) && \begin{array}{l}\text{By the associative property}\\\text{of multiplication}\end{array}\\&=\sqrt{2} \times 12\\ &= 12\sqrt{2}\end{aligned}$ .

4 0

3 years ago

Read 2 more answers

The perimeter of a rectangular backyard is 146 feet. It is 40 feet long. How wide is it?

asambeis [7]

9514 1404 393

Answer:

33 ft

Step-by-step explanation:

The perimeter formula for a rectangle is ...

P = 2(L +W)

Filling in the given numbers, we have ...

146 = 2(40 +W)

73 = 40 +W . . . . . . . divide by 2

33 = W . . . . . . . . . . . subtract 40

The backyard is 33 feet wide.

7 0

3 years ago

Solve for x X/6 = 10 A) X = 4 B) X = 10 C) X = 16 D) X = 60

Lina20 [59]

hi

x/6 = 10

In a equation , you can use every math operation you know as long as you do the same thing on both sides.

Here we have x/6 = 10

But what I want is x .

Here X is split in 6. So I 'm going to multiplicate all by 6 to find the original amount of X

In bold operation that are often not written but that you must understand to do that kind of exercices.

So : x/6 = 10

(x/6) *6 = 10 *6

6x/6 = 60

x = 60

4 0

3 years ago

The length of a table is 110 cm to the nearest cm

bogdanovich [222]

Answer: they didn’t give the exact answer.

Step-by-step explanation: they rounded to the nearest.

7 0

4 years ago

Please help me. This is real confusing.

katrin2010 [14]

Answer:

1st problem: b) $A=2500(1.01)^{12t}$

2nd problem: c) $A=2500e^{.12t}$

Step-by-step explanation:

1st problem:

The formula/equation you want to use is:

$A=P(1+\frac{r}{n})^{nt}$

where

t=number of years

A=amount he will owe in t years

P=principal (initial amount)

r=rate

n=number of times the interest is compounded per year t.

We are given:

P=2500

r=12%=.12

n=12 (since there are 12 months in a year and the interest is being compounded per month)

$A=2500(1+\frac{.12}{12})^{12t}$

Time to clean up the inside of the ( ).

$A=2500(1+.01)^{12t}$

$A=2500(1.01)^{12t}$

----------------------------------------------------

2nd Problem:

Compounded continuously problems use base as e.

$A=Pe^{rt}$

P is still the principal

r is still the rate

t is still the number of years

A is still the amount.

You are given:

P=2500

r=12%=.12

Let's plug that information in:

$A=2500e^{.12t}$ .

6 0

3 years ago