The average rate of change of the function is: 3.2.
<h3>What is the Average Rate of Change for a Function?</h3>
Average rate of change = 
Given the function,
, the average rate of change over the interval of x = 2 to x = 6 would be calculated as shown below:
a = 2
b = 6
f(a) = f(2) = 3.2(2) + 25 = 31.4
f(b) = f(6) = 3.2(6) + 25 = 44.2
Average rate of change = (44.2 - 31.4)/(6 - 2) = 3.2.
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a(b+c)=ab+ac
2(2.5q+8)=2(2.5q)+2(8)=5q+16
1-5q+5q+16
1+0+16
17
Answer:
7. Mean = 48
Median = 47.5
Mode = 72
Range = 66
8. Mean= 59.625
Median = 61
Mode = 90
Range = 79
9. Mean = 31.57
Median = 32
Mode = 46
Range = 34
10. Mean = 42.11
Median = 36
Mode = 51
Range = 51
Step-by-step explanation:
Mean is the average. Mode is the number that appears the most. Median is the middle number. Range is the biggest number minus the smallest number.
Hope this helps.
Answer:
19/20
Step-by-step explanation:
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Answer:
RADIUS
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PROBLEM
Mary’s bicycle wheel has a circumference of 226.08 cm². What is its radius?
SOLUTION
We can solve this problem using the circumference formula in which π stands for ( 3.14 ), C stands for circumference itself and r stands for radius.
\bold{Formula \: || \: C = 2πr}Formula∣∣C=2πr
\tt{226.08 = 2(3.14) r}226.08=2(3.14)r
'Now to find the radius,Substitute 226.08 for c which is circumference in the formula.
\begin{gathered} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \tt{C = 2πr} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \tt{226.08 = 2(3.14)\red{r}} \\ \\ \: \: \: \: \: \: \: \: \large \tt{ \frac{226.08}{6.28} = \cancel\frac{6.28 \red{r}}{6.28} } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{\tt\green{C = 36}}\end{gathered}
C=2πr
226.08=2(3.14)r
6.28
226.08
=
6.28
6.28r
C=36
To check:
\begin{gathered} \small\begin{array}{|c|}\hline \bold{circumference }\\ \\ \tt{C = 2πr} \\ \tt{C = 2(3.14) (36\:cm) } \\ \tt{C = 2(113.04\:cm) } \\ \underline{\tt \green{C = 226.08\:cm }} \\ \hline \end{array} \end{gathered}
circumference
C=2πr
C=2(3.14)(36cm)
C=2(113.04cm)
C=226.08cm
FINAL ANSWER
If Mary's Bicycle has a circumference of 226.08 cm then the radius is 36.
\boxed{ \tt \red{r = 36}}
r=36
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