D is the answer hope this helps
Step-by-step explanation:
YES! HOP THIS HELPS
Answer:
The total of all the boxes would be $5.00.
Margin of error, e = Z*SD/Sqrt (N), where N = Sample population
Assuming a 95% confidence interval and substituting all the values;
At 95% confidence, Z = 1.96
Therefore,
0.23 = 1.96*1.9/Sqrt (N)
Sqrt (N) = 1.96*1.9/0.23
N = (1.96*1.9/0.23)^2 = 262.16 ≈ 263
Minimum sample size required is 263 students.
Answer:
<em>B. 11 - 6 = 5</em>
Step-by-step explanation:
Median: 9.5
Lower Quartile: 6
Upper Quartile: 11
Interquartile Range: upper quartile - lower quartile = answer
