Answer:
30.17feet high
Step-by-step explanation:
Given the following
the distance from the base of the pole to the tip of the shadow = 49feet (hypotenuse)
angle of elevation = 38°
Required
Height of the flagpole (opposite)
Using the SOH CAH TOA identity
Sin theta = opposite/hypotenuse
Sin 38 = H/49
H = 49sin38
H = 49(0.6157)
H = 30.17feet
Hence the flagpole is 30.17feet high
Not too sure what you're asking, but...
3(x+2) is the expression
Answer:
The sign of each y-coordinate changed.
Step-by-step explanation:
This was a reflection over the x-axis.
If you look at point F, it is (-5, -1) the corresponding point F' is (-5,1). Notice the numerical values of x and y are the same, but the sign of y flipped from negative to positive. The other four points all follow the same pattern.