Answer:

Step-by-step explanation:
Given expression:



Replace 900 with 30² :




(We need to use the absolute value of √x² since the x term was originally to the power of 2, which means the value of x² is always positive since the exponent is even).


Simplify:

(We need to use the absolute value of z³ since the z term was original to the power of 6, which means the value of z⁶ is always positive since the exponent is even).
Answer:
False
Step-by-step explanation:
8x2=16
16-63=-47
-47=-40
The numbers do not match.
Hence, the equation is false.
<em>QUESTION:</em>
<em>QUESTION:estimate the equation 12+19.61.</em>
<em>QUESTION:estimate the equation 12+19.61.Answer:</em>
<em>QUESTION:estimate the equation 12+19.61.Answer:12+19.61 =31.61.</em>
The answer to your question is option b


So it is the product of

And 2,5 and 11 are prime numbers, so there you go :)