The four inequalities that can be used to find the solution of 3 ≤ |x + 2| ≤ 6 is x + 2 ≤ 6, x + 2 ≥ -6, x + 2 ≥ 3 and x + 2 ≤ -3
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
Given the inequality:
3 ≤ |x + 2| ≤ 6
Hence:
x + 2 ≤ 6, -(x + 2) ≤ 6, 3 ≤ x + 2 and 3 ≤ -(x + 2)
This gives:
x + 2 ≤ 6, x + 2 ≥ -6, x + 2 ≥ 3 and x + 2 ≤ -3
The four inequalities that can be used to find the solution of 3 ≤ |x + 2| ≤ 6 is x + 2 ≤ 6, x + 2 ≥ -6, x + 2 ≥ 3 and x + 2 ≤ -3
Find out more on equation at: brainly.com/question/2972832
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Answer:
183590
Step-by-step explanation:
1/2(600)^2+6(600)-10
1/2(360000)+6(600)-10
180000+3600−10
183590
Answer: Rounded to the nearest tenth is 5
4.96894409 is the exact answer
Answer:
The given points are
The setting would have a interval or 2 units above and below the minimum and maximum of each coordinate.
The given maxium horizontal coordinate is 0.
The given minimum horizontal coordinate is -13.
The given maximum vertical coordinate is 3.
The given minimum vertical coordinate is -7.
Now, we extend each maximum and minimum value by 2 units to create the setting.
So, the setting is
With a scale of 2 units.
