Answer:
V = 288.5 
Step-by-step explanation:
To find the volume of a cone, use this equation:
r = radius
h = height
We aren't given the height of the cone, just the length of the side. To find the height use the Pythagorean Theorem:
The value of 12.1 yds is the hypotenuse and the radius is the value of one of the legs. So, set it up like this:
Now, solve:
Distribute the square
Subtract 25 from 146.41
a = 11.01862
So, the height is equal to 11.01862 yds.
Now, we can plug everything into the volume equation:
Simplify (use calculator):
V = 288.5
So, the volume of the cone is equal to 288.5
The Great Pyramids of Khufu is located in El Giza, Egypt. Pyramids were built to serve as tombs for the pharaohs of ancient Egypt. The Great Pyramid is 481 feet high and has a square base with a base edge length of 756 feet. What is the approximate surface area (to the nearest hundredth) of the pyramid.
(HINT: Is the base on the surface?)
Square with edge length = 756 feet
Square= 1/2 × 297.45 × 481
= 286,146.9ft
= 1,037,709,9ft. base with edge length =756 feet
area of square,
= Side² = 756 × 756 = 571,563ft²
⇒ area of base = 1/2 = 756/2 = 378ft
By pythagorean theorem,
H² = P²+B²
(481)² = P²+(378)²
P² = (481)²-(378)²
P² = 231,361-142,884
P² = 88,477
P = √88,477
P = 297.45
Area of triangle =1/2 × b × h
= 1/2x297.45*481
= 148.725×481
= 71,536.725
Now 4 area of triangle = 4×71,536.725
= 286,146.9ft
total surface area of pyramid + square
= 751,563+286,146.
= 1,037,709,9ft.
Answer:
Step-by-step explanation:
Work is said to be done when a force applied to an object cause the body to move in a specified direction.
Work-done = Force * Distance
Since Force = mass * acceleration due to gravity
Work-done = mass * acceleration due to gravity * distance
Given mass = 1.4kg, distance = 0.7m and g = 9.8m/s²
Workdone in lifting the book off the floor = 1.4*0.7*9.8
Workdone = 9.604Joules
- Similarly, work done in lifting a 21-lb weight book 6 ft off the ground is expressed using the same formula as above;
Given mass = 21-lb, g = 32ft/s² and distance = 6ft
Workdone = 21 * 32 * 6
Workdone = 4,032 lb-ft²/s²
Hence, work-done in lifting a 21-lb weight book 6 ft off the ground is 4,032 lb-ft²/s²
The mean score for men would be 8.26
Answer:40=6
Step-by-step explanation:
