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3 years ago

How are <1 and <2 related

Mathematics

1 answer:

Stella [2.4K]3 years ago

3 0

Answer:

They are adjacent

Step-by-step explanation:

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Use the distributive property to find the product.

VladimirAG [237]

A Is your answer :D

W^2 + 2W + 3

4 0

3 years ago

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A square is made up of an L-shaped region and three transformations of the region. If the perimeter of the square is 40 units, w

Mila [183]

Answer:

20 units

Step-by-step explanation:

This implies that the square can be divided into four equal L-shaped regions. These regions with respect to transformation forms a square.

Perimeter of the square is 40 units. Since a square has equal length of sides, thus each side of the square is 10 units.

Thus, each L-shape region has dimensions; 8 units, 5 units, 5 units and 2 units.

Perimeter of each L-shape region = the addition of the length of each side of the shape

Perimeter of each L-shape region = 8 + 5 + 5 + 2

= 20 units

3 0

3 years ago

10 points

oee [108]

Answer:

x = 240 feet

Step-by-step explanation:

It is given that,

The angle of depression is 30 degrees from the bottom of the boat to a deep sea diver at the depth of 120 ft.

We need to find the distance x the diver must swim up to the boat. It can be calculate by applying trigonometry as follows :

$\sin30=\dfrac{120}{x}\\\\x=\dfrac{120}{\sin30}\\\\x=240\ \text{feet}$

So, the distance the diver must swim up to the boat is 240 feet.

6 0

3 years ago

What is c in 6c + 3y = 18 if y is 2?

Natali [406]

Answer:

c = 2

Step-by-step explanation:

6c + 3y = 18

6c + 3(2) = 18

6c + 6 = 18

6c = 12

c = 2

6 0

3 years ago

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Drag the tiles to the correct boxes to complete the palrs.

Brut [27]

Answer:

(f+g)(2) = 4

(f-g)(4) = 8

(f ÷g)(2) = 7

(f x g)(1) = 0

Step-by-step explanation:

We are given these following functions:

$f(x) = 2x + 3$

$g(x) = x - 1$

(f+g)(2)

$(f+g)(x) = f(x) + g(x) = 2x + 3 + x - 1 = 3x - 2$

At $x = 2$

$(f+g)(2) = 3(2) - 2 = 6 - 2 = 4$

Then

(f+g)(2) = 4

(f-g)(4)

$(f-g)(x) = f(x) - g(x) = 2x + 3 - (x - 1) = 2x + 3 - x + 1 = x + 4$

At x = 4

$(f-g)(4) = 4 + 4 = 8$

Then

(f-g)(4) = 8

(f ÷g)(2)

$(f \div g)(x) = \frac{f(x)}{g(x)} = \frac{2x+3}{x-1}$

At x = 2

$(f \div g)(2) = \frac{7}{1} = 7$

Then

(f ÷g)(2) = 7

(f x g)(1)

$(f \times g)(x) = f(x)g(x) = (2x+3)(x-1) = 2x^2 -2x + 3x - 3 = 2x^2 + x - 3$

Then

$(f \times g)(1) = 2(1)^2 + 1 - 3 = 3 + 1 - 3 = 0$

(f x g)(1) = 0

4 0

3 years ago