We have 2 types of tickets, A tickets and B tickets. The total number of tickets sold was 500, so an equation for this NUMBER of tickets is A + B = 500. The MONEY equation is something different. A tickets cost 10, so they are represented by 10A; B tickets cost 60, so they are represented by 60B. The total dollar sales for A and B are 6000. Our money equation for the sales is 10A + 60B = 6000. Solve the first equation for A: A = 500 - B. Sub that value for A into the second equation to solve for B: 10(500-B) + 60B = 6000. Distribute through the parenthesis to get 5000 - 10B + 60B = 6000. Combine like terms to get 50B = 1000. B = 20. There were 20 type B tickets sold. A = 500 - B, so A = 500 - 20 and A = 480. There were 480 type A tickets sold.
Answer:
-13/6 or (in mixed number form) -2 1/6
Step-by-step explanation:
Rewriting our equation with parts separated
=10+512−12−712
Solving the whole number parts
10−12=−2
Solving the fraction parts
512−712=−212
Reducing the fraction part, 2/12,
−212=−16
Combining the whole and fraction parts
−2−16=−216
Another way to do it:
Convert any mixed numbers to fractions.
Then your initial equation becomes:
125/12−151/12
Applying the fractions formula for subtraction,
=(125×12)−(151×12) / 12×12
=1500 − 1812/ 144
=−312/144
Simplifying -312/144, the answer is
=−2 1/6
Answer:
3
Step-by-step explanation:
why would a goose have hens
It be 81.
You have to take half of -18 which is -9, and square that, which is 81.
Answer: 800
Step-by-step explanation:
