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Sati [7]
3 years ago
15

Please Help. For My Math Test. Due Soon.

Mathematics
1 answer:
cricket20 [7]3 years ago
7 0

Answer:

\frac{1}{3} * 20 -5  = \frac{20}{3} - 5 = \frac{5}{3} .

5/3 is the answer

Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just don’t want to waste my time in case you don’t want me to :)

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Solve for y<br> 4.2x - 1.4y = 2.1
Harlamova29_29 [7]
4.2x - 1.4y = 2.1    |multiply both sides by 10

42x - 14y = 21    |subtract 42x from both sides

-14y = 21 - 42x    |change signs

14y = 42x - 21    |divide both sides by 14

y = 3x - 1.5
8 0
4 years ago
Solve for X
satela [25.4K]

Answer:

3)  16

Step-by-step explanation:

these are alternate-interior angles which are congruent

10x-23 = 137

10x = 160

x = 16

4 0
3 years ago
Read 2 more answers
Which expressions are completely factored? Select each correct answer. 18y^3−6y=3y(6y^2−2) 32y^10−24=8(4y^10−3) 20y^7+10y^2=5y(4
Vladimir79 [104]

Answer:

The expressions that completely factored are:

32y^{10}-24 = 8(y^{10}-3) ⇒ 2nd

16y^{5}+12y^{3}=4y^{3}(4y^{2}+3) ⇒ 4th

Step-by-step explanation:

Complete factorization means the terms in the bracket has no common factor

∵ The expression is 18y³ - 6y

- Find the greatest common factor of the numbers and the variable

∵ The greatest common factor of 18 and 6 is 6

∵ The greatest common factor of y³ and y is y

∴ The greatest common factor is 6y

- Divide each term by 6y to find the terms in the bracket

∴ 18y³ - 6y = 6y(3y² - 1) ⇒ not the same with the answer

∵ The expression is 32y^{10}-24

∵ The greatest common factor of 32 and 24 is 8

∴ The greatest common factor is 8

- Divide each term by 8 to find the terms in the bracket

∴ 32y^{10}-24 = 8(  y^{10}-3)  ⇒ the same with the answer

∴ The expression 32y^{10}-24 = 8(y^{10}-3) is completely factored

∵ The expression is 20y^{7}+10y^{2}

∵ The greatest common factor of 20 and 10 is 10

∵ The greatest common factor of y^{7} and y² is y²

∴ The greatest common factor is 10y²

- Divide each term by 10y² to find the terms in the bracket

∴ 20y^{7}+10y^{2}=10y^{2}(2y^{5}+1) ⇒ not the same with the answer

∵ The expression is 16y^{5}+12y^{3}

∵ The greatest common factor of 16 and 12 is 4

∵ The greatest common factor of y^{5} and y³ is y³

∴ The greatest common factor is 4y³

- Divide each term by 4y³ to find the terms in the bracket

∴ 16y^{5}+12y^{3}=4y^{3}(4y^{2}+3) ⇒ the same with the answer

∴ The expression 16y^{5}+12y^{3}=4y^{3}(4y^{2}+3) is completely factored

The expressions that completely factored are:

32y^{10}-24 = 8(y^{10}-3)

16y^{5}+12y^{3}=4y^{3}(4y^{2}+3)

3 0
3 years ago
PLS HELP WITH THIS I NEED A GOOD GRADE
Minchanka [31]

Step-by-step explanation:

<h2>4.5 approximately is the answer.</h2>

4 0
3 years ago
If the scale on a map shows 1 in. = 100 mi., and you determine that two cities are 5.5 in. apart, how many actual miles is this?
Anna007 [38]

Answer:

550 mi. !!!!

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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