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3 years ago

Jasmine works at the public library after school. She makes $7.00 per hour. She cannot work more than 15 hours per

Mathematics

1 answer:

sveta [45]3 years ago

3 0

Answer:

the answer is mx +B plus the quradratic formula

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Susan charges $8 per hour walking her neighbor’s dog. She charges $12 per hour babysitting. Part A: Define the variables. Part B

Anna35 [415]

Answer:

the total she earns with "d" hours of dog walking and "b" hours of babysitting is given by: 8 d + 12 b

Step-by-step explanation:

If we use "d" to represent the number of hours that Susan walks the dog, and we define "b" as the number of hours she babysits, then the expression that represents the amount she earns by walking the dog is: $8 times d = 8 d

Similarly, the amount she earns by babysitting is $12 times b = 12 b

Then the total she earns with "d" hours of dog walking and "b" hours of babysitting is: 8 d + 12 b

7 0

3 years ago

one third of the bagels ina bakery are sesame bagels. there are 72 sesame bagels. define a variable. then write and solve an equ

Sholpan [36]

Bagels = x
sesame bagels = x/3 = 72

x/3=72
x=72x3
x=216

7 0

3 years ago

Please help with the answer, the one chosen is not correct

ZanzabumX [31]

Answer:

it's c.

Step-by-step explanation:

Because science

8 0

3 years ago

What is the square root of 36? A.4 B.6 C.8 D.10

Arisa [49]

Answer:

B 6

Step-by-step explanation:

because 6x6 is 36

3 0

3 years ago

Read 2 more answers

Apply the power of a power property to simplify y 4/3• y 2/3 - 1/2 = y2- - 1/2 =

prohojiy [21]

Answer:

$y^{ \frac{3}{2}}$

Step-by-step explanation:

From the question posted, you've already initiated the solution but you applied a wrong approach;

Given

$y^{\frac{4}{3}} . y^{\frac{2}{3} - \frac{1}{2}}$

Required

Simplify; using power property

Power property states that;

$a^m.a^n = a^{m+n}$

$a^m/a^n = a^{m-n}$

By comparison; we have to apply the first property;

This is shown below;

$y^{\frac{4}{3}+\frac{2}{3} - \frac{1}{2}}$

Add fraction of the same numerator

$y^{\frac{4+2}{3} - \frac{1}{2}}$

$y^{\frac{6}{3} - \frac{1}{2}}$

$y^{2 - \frac{1}{2}}$

Subtract fraction

$y^{ \frac{4-1}{2}}$

$y^{ \frac{3}{2}}$

The expression $y^{\frac{4}{3}} . y^{\frac{2}{3} - \frac{1}{2}}$ is equivalent to $y^{ \frac{3}{2}}$

8 0

3 years ago

Read 2 more answers