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S_A_V [24]
3 years ago
10

Kaitaia has one more than 5 times the number or wristbands that shelly has. Rea has three more than twice the number that shelly

has. What expression would show how many more wristbands katia has the Rea
Mathematics
2 answers:
saul85 [17]3 years ago
3 0

Answer: The required expression is 3x+4.

Step-by-step explanation:

Since we have given that

Let the number of wristbands that Shelly has be 'x'

Let the number of wristbands that Kaitaia has be 5x+1

Let the number of wristbands that Rea has be three more than twice the number that shelly has be

'2x+3'

According to question, the expression that shows the number of wristbands more Katia has than Rea is given by

5x+1-(2x-3)\\\\=5x+1-2x+3\\\\=3x+4

Hence, the required expression is 3x+4.

mixer [17]3 years ago
3 0

Answer:

Step-by-step explanation:

Let Shelly has p number of wrist bands.

Rea has 3 more than twice the number that Shelly has

So, Rea has 3 + 2p wrist bands

Kaitaia has one more than 5 times the number that Shelly has

So, Kaitaia has 1 + 5p wrist bands

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