180 N
Step by Step Explanation :
Step 1 :
Given that the buoyant force of the boat is 260 N
and the boat's weight is 80 N
We have to find the maximum weight capacity of the boat so that it continues to float.
The boat would float when the total of the weight of boat and the load it carries do not exceed the buoyant force.
Step 2 :
The weight capacity of the boat is therefore 260 N - 80 N = 180 N
Hence the boat can carry a weight of 180 N to continue to float
Answer:
X is 12 Y is 124
Step-by-step explanation:
left and right side have equal degrees of 56
so x would be 12 because you would multiply 4×12
since in total it will be 360 degrees
you add 56 and 56 together to get 112
then just subtract 112 from 360 and you get 248 then divide 248 by 2 and you have your bottom and top value of 124
Answer:
387
Step-by-step explanation:
Answer:
30 SQUARE units
Step-by-step explanation:
Since the problem only includes two dimensions, we solve for area, not volume. Area=width*height, or 3*10=30. Because we're solving for area the answer is 30 square units.
Answer:
After 2 seconds
Step-by-step explanation:
First step is find an equation of velocity:
h(t)=-16t2+64t+112. The velocity function is derivated from position function, so we should do that.
v(t)= h´(t)= -16*2*t+64 ⇒ v(t)= -32t+64.
Now we know the arrow reach the maximun height when this velocity is equal to zero when t>0.
0=-32t+64 ⇒ 32t=64, split each member for 32 ⇒ 
=
t=2. That means after 2 sec. the arrow reach the maximum height
