Answer:
youngest 17
middle 19
oldest 21
Step-by-step explanation:
Three sisters have ages that are consecutive odd integers
youngest = x
middle = x + 2
oldest = x + 4
--------------------
The sum of the age of the youngest
x
and three times the age of the oldest
+ 3(x + 4)
is five less than five times the middle sister’s age
= 5(x + 2) - 5
-----------------------
x + 3(x + 4) = 5(x + 2) - 5
Distribute
x + 3x + 12 = 5x + 10 - 5
Combine like terms
4x + 12 = 5x - 5
Subtract 4x from both sides
12 = x - 5
Add 5 to both sides
17 = x
youngest x = 17
middle x + 2 = 19
oldest x + 4 = 21
18a:16 18b:32 % means out of 100
Here's the formula:
(y2-y1)/(x2-x1)
so then:
(p-3)/(21-9)
so:
p-3/(12)
so then p = 7
Hey There!
This is the answer because the GCF of both fractions is 2.
Thank You!
