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Elan Coil [88]
3 years ago
13

What is the equivalent fraction to 4/20​

Mathematics
2 answers:
AlladinOne [14]3 years ago
6 0

Answer:

3/15

Step-by-step explanation:

AnnZ [28]3 years ago
6 0
3/15, 2/10, 1/5, 6/30..
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Find the values of the three missing values in the parallelogram the diagram is not to scale
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Parallelogram so opposite sites are parallel
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<1 = 113
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HELP PLEASE!<br> Solve for m.<br><br> 3.6m = 14.4
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Answer:

4m

Step-by-step explanation:

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I need help ASAP! Thanks.
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Sonja [21]
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4 0
3 years ago
Car X weighs 136 pounds more than car Z. Car Y weighs 117 pounds more than car Z. The total weight of all three cars is 9439 pou
Aleksandr [31]

Let x, y and z denote the weighs of car X, car Y and car Z, respectively.

We know that car X weighs 136 more than car Z, this can be express by the equation:

x=z+136

We also know that Y weighs 117 pounds more than car Z, this can be express as:

y=z+117

Finally, we know that the total weight of all the cars is 9439, then we have:

x+y+z=9439

Hence, we have the system of the equations:

\begin{gathered} x=z+136 \\ y=z+117 \\ z+y+z=9439 \end{gathered}

To solve the system we can plug the values of x and y, given in the first two equations, in the last equation; then we have:

\begin{gathered} z+136+z+117+z=9439 \\ 3z=9439-136-117 \\ 3z=9186 \\ z=\frac{9186}{3} \\ z=3062 \end{gathered}

Now that we have the value of z we plug it in the first two equations to find x and y:

\begin{gathered} x=3062+136=3198 \\ y=3062+117=3179 \end{gathered}

Therefore, car X weighs 3198 pound, car Y weighs 3179 pounds and car Z weighs 3062 pounds.

4 0
2 years ago
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