Building time :
4c + 6a < = 120
testing time :
4c + 4a < = 100
20 child bikes and 6 adult bikes...c = 20 and a = 6
sub into both equations
4c + 6a < = 120
4(20) + 6(6) < = 120
80 + 36 < = 120
116 < = 120 (correct)
4c + 4a < = 100
4(20) + 4(6) < = 100
80 + 24 < = 100
104 < = 100 (incorrect)
ur answer : No, because the bike order does not meet the restrictions of 4c + 6a < = 120 and 4c + 4a < = 100
Answer:
D
Step-by-step explanation:
Answer:
Can you put the graphs up then ill edit my answer and give you the answer
Answers:
The length of XY is 4
The length of ZW is 6
Because we don't get the same length (for XY and ZW), this means that the segments are not congruent.
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To find the length of segment XY, you can count the number of spaces between -7 and -3 to get 4 units. Or you can subtract and use the absolute value notation to ensure the result is positive
|-7-(-3)| = |-7+3| = |-4| = 4
Do the same for segment ZW.
|2-8| = |-6| = 6
