The square root of a a negative integer is imaginary.
It would still be a negative under a square root if you multiplied it by 2, therefor it will still be imaginary, or I’m assuming as your book calls it, undefined.
2•(sqrt-1) = 2sqrt-1
If you add a number to -1 itself, specifically 1 or greater it will become a positive number or 0 assuming you just add 1. In that case it would be defined.
-1 + 1 = 0
-1 + 2 = 1
If you add a number to the entire thing “sqrt-1” it will not be defined.
(sqrt-1) + 1 = 1+ (sqrt-1)
If you subtract a number it will still have a negative under a square root, meaning it would be undefined.
(sqrt-1) + 1 = 1 + (sqrt-1)
however if you subtract a negative number from -1 itself, you end up getting a positive number or zero. (Subtracting a negative number is adding because the negative signs cancel out).
-1 - -1 = 0
-1 - -2 = 1
If you squared it you would get -1, which is defined
sqrt-1 • sqrt-1 = -1
and if you cubed it, you would get a negative under a square root again, therefor it would be undefined.
sqrt-1 • sqrt-1 • sqrt-1 = -1 • sqrt-1 = -1(sqrt-1)
Sorry if this answer is confusing, I don’t have a scientific keyboard, I’ll get one soon.
Just multiply the with and the length by four (considering the scale factor is 4)
3x4=12 and 7x4=28
Answer:
2y - 3x = -15
Step-by-step explanation:
Slope of the line 4x + 6y = 1 is as shown below;
Rewrite in slope intercept form;
6y = -4x+1
y = -4x/6 + 1/6
y = -2x/3 + 1/6
mx = -2/3x
m = -2/3
The slope of the line perpendicular M = -1/(-2/3)
M = 3/2
Get the x and y intercept of 2x+3y = 18
x intercept occurs when y = 0
2x + 0 = 18
x= 18/2
x = 9
y intercept occurs when x = 0
0 + 3y = 18
3y= 18
y = 18/3
y = 6
The line passes through the point (9,6)
Write the equation in point slope form
y - y0 = m(x-x0)
y - 6 = 3/2(x-9)
2(y-6) = 3(x-9)
2y - 12 = 3x - 27
2y - 3x = -27 + 12
2y - 3x = -15
This gives the required equation
4= A because it's greater than or equal to 30 minutes of reading a day and 5 = D because all of the answers are greater than the equation.
