Answer:
The ratio of the drag coefficients is approximately 0.0002
Step-by-step explanation:
The given Reynolds number of the model = The Reynolds number of the prototype
The drag coefficient of the model, = The drag coefficient of the prototype,
The medium of the test for the model, = The medium of the test for the prototype,
The drag force is given as follows;
We have;
Therefore;
= (1/17)^3 ≈ 0.0002
The ratio of the drag coefficients ≈ 0.0002.
Answer:
f(x) = 2x3 + 4
Stretch vertically be a factor of 2:
f(x) = 2*2x3 + 4 = 4x3 + 4
Shift 5 units to the left:
f(x) = 4(x+5)3 + 4
Volume of cone=(1/3)hpir^2
d/2=r
d=2
d/2=2/2=1=r
h=6
V=(1/3)6pi1^2
V=2pi in^3 is volume
ratio of 2:1
2+1=3
2pi=3 units
divide both sides by 3
2/3pi=1 unit
vanila=2 units
times 2/3pi by 2
4/3pi
aprox pi=3.141592
4.188
round
4.2 in^3 of vanilla
$16.67 would be the price of each pencil. You divide 50 by 3 and get 16.6 repeating so you round it up to 16.67