Answer:
22.86% probability that the persons IQ is between 110 and 130
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
If one person is randomly selected what is the probability that the persons IQ is between 110 and 130
This is the pvalue of Z when X = 130 subtracted by the pvalue of Z when X = 110.
X = 130
has a pvalue of 0.9772
X = 110
has a pvalue of 0.7486
0.9772 - 0.7486 = 0.2286
22.86% probability that the persons IQ is between 110 and 130
Answer:
It is 9a2 − 30a + 25 The other answer is a prime number.
(
3a
−5)^2
Step-by-step explanation:
Answer:
5.5 gallons
Step-by-step explanation:
There are 4 quarts in 1 gallon.
22 ÷ 4 = 5.5
I hope this helps :)
This is an answer should help you
80$ because 50 divided by 3 is 16.67 and 80 divided by 5 is 16 so yeah $80