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yaroslaw [1]
4 years ago
6

Use the associative property to identify which expression is equal to (32)(8)(5x).

Mathematics
1 answer:
kondaur [170]4 years ago
6 0
Associative property groups numbers but the order stays the same.
If the '.' In C mean multiply then this is the answer.
None of the others are.
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In triangle XYZ, A is the midpoint of XY, B is the midpoint for YZ, and C is the midpoint of XZ. Also,
azamat

Answer:

Perimeter of Δ ABC = 7 + 8 + 9 = 24 cm

Step-by-step explanation:

In  triangle Δ XYZ ,

A is the mid point of XY

B is the midpoint of YZ

C is the mid point of XZ

AY = 7

BZ =8

XZ = 18

The mid - point theorem states that,

The segment formed by connecting two mid - points of a triangle is parallel to the third side and half as long

AY = 7 then BC = 7 cm

BZ = 8 then AC = 8 cm

XY = 18 then AB = 9 cm

Perimeter of Δ ABC = 7 + 8 + 9 = 24 cm

8 0
4 years ago
Enter the value for x that makes the equation 1/2 (4x+12)+5x=30 true.
8090 [49]
First, distribute the (1/2) into (4x+12) by multiplying them.

The equation becomes:

2x + 6 + 5x = 30

On the left side, combine “like terms” through addition.

7x + 6 = 30

Subtract 6 from both sides:

7x = 24

Finally, get x alone by dividing both sides by 7:

x = 24/7, or if you wanted to round the decimal answer, it’s about 3.429.
8 0
3 years ago
18. A I-10 number cube is rolled. What is the conditional probability that the number rolled is less than 6, given that the numb
Romashka-Z-Leto [24]

Answer:

30% Probability

Step-by-step explanation: 3/10=0.3

6 0
3 years ago
Write the equation of a line that passes through the points (-1, -4) and (1, 3).
Elan Coil [88]

Answer:

y=3.5x-.5

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find the zeros of polynomial function and solve polynomials equations.<br> f(x)=24x^3-64x^2-21x+56
8090 [49]

Since this polynomial has 4 terms, factoring by grouping should be the first thing we try here.

So, we have:

8x^2(3x-8)-7(3x-8)=0 \implies\\ (8x^2-7)(3x-8)=0

So, we can use ZPP to find out roots:

3x-8 =0 \implies\\ x=\frac{8}{3}\\ 8x^2-7=0 \implies \\ 8x^2=7 \implies \\ x^2=\frac{7}{8} \implies \\ x=\pm\frac{\sqrt{7}}{\sqrt{{8}}}\\ \text{Rationalizing denominator:}\\ x=\pm\frac{\sqrt{56}}{8}

So our three roots are:

x \in \{\frac{8}{3},\frac{\sqrt{56}}{8},-\frac{\sqrt{56}}{8}\}

8 0
3 years ago
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