5pi/12 radians
The arc measure is 75, so theta must also be the same. if theta is 75, and 75 in radians is 5pi/12 radians, then the answer is that.
Answer:
Caleb arrived first 2 hours before Alyssa
Step-by-step explanation:
To solve the situation, find the speed per hour they were driving by dividing the distance they drove by the time it took.
Alyssa drove 105 miles in 3.5 hours or 105/3.5 = 30 miles per hour.
Caleb drove 168 miles in 4 hours or 168/4 = 42 miles per hour.
Since they both left at the same time and drove the same 210 miles to the beach, Caleb arrived first since he was driving faster.
He arrived in 210/42 = 5 hours.
Alyssa arrived in 210/30 = 7 hours.
He arrived 2 hours before her.
m<P would be:
25
but m<PQC I forgot how to do... sorry!
You can do that using +6 and -6 .
(6) · (-6) = - 36
(6) + (-6) = 0
Answer:
The 90% confidence interval for the mean nicotine content of this brand of cigarette is between 20.3 milligrams and 30.3 milligrams.
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 9 - 1 = 8
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 8 degrees of freedom(y-axis) and a confidence level of
. So we have T = 1.8595
The margin of error is:
M = T*s = 1.8595*2.7 = 5
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 25.3 - 5 = 20.3 milligrams
The upper end of the interval is the sample mean added to M. So it is 25.3 + 5 = 30.3 milligrams.
The 90% confidence interval for the mean nicotine content of this brand of cigarette is between 20.3 milligrams and 30.3 milligrams.