So to find x we need to add both HI and IJ - which we know equals 7:
Then we need to combine like terms:
And then set equal to 0:
Then we can factor:
So then when we set each term equal to 0 individually and solve for x we get: x = -5 and x = -2.
So we have these two values - we need to test which one is correct. So if we go back to the HI segment, let's try plugging in x = -5:
This gives us a negative number, which we know that length cannot be negative. Let's try x = -2:
This gives us a positive length and therefore we can keep this value.
So the answer is: x = -2.
2x=peaches
<span>x=nectarines </span>
<span>2x+x=168</span>
<span>3x=168</span>
<span>x=168/3</span>
<span>x=56
</span>
<span>2(56) = 112 </span>
<span>56 nectarines and 112 peaches</span>
BET I WILL BRUH I GOT CHU
<h3>
Answer:</h3>
- a_n = -3a_(n-1); a_1 = 2
- a_n = 2·(-3)^(n-1)
<h3>
Step-by-step explanation:</h3>
A) The problem statement tells you it is a geometric sequence, so you know each term is some multiple of the one before. The first terms of the sequence are given, so you know the first term. The common ratio (the multiplier of interest) is the ratio of the second term to the first (or any term to the one before), -6/2 = -3.
So, the recursive definition is ...
... a_1 = 2
... a_n = -3·a_(n-1)
B) The explicit formula is, in general, ...
... a_n = a_1 · r^(n -1)
where r is the common ratio and a_1 is the first term. Filling in the known values, this is ...
... a_n = 2·(-3)^(n-1)
