Answer:
18x^2 y^8
Step-by-step explanation:
2(-3xy^4)^2
We know that (ab)^x = a^x b^x
2 * (-3)^2 x^2 y^4^2
2 *9 x^2 y^4^2
We know that a^b^c = a^(b*c)
18 x^2 y^(4*2)
18x^2 y^8
Answer:
The answer is 5y + 12
Step-by-step explanation:
=8y - 3y + 12
=5y + 12
I think you meant to say the ratio of the areas (not perimeters). Also, HKO and FGO are not showing up, so it seems like a different problem. I'm going to answer the question you posted in the image attachments.
The triangle ABC has area 12 since
A = b*h/2 = 4*6/2 = 24/2 = 12
Triangle CEF has area 48 because
A = b*h/2 = 8*12/2 = 96/2 = 48
The ratio of the areas is found by dividing the area of ABC over the area of CEF (as the last box instructs) so we have 12/48 = 1/4
Therefore, the area of ABC is 1/4 that of the area of CEF
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In summary,
<h3>Answer for the first box: 12</h3><h3>Answer for the second box: 48</h3><h3>Answer for the third box: 1/4</h3>
