Refer to the diagram shown below.
h = the height of the cliff.
d = the distance of the landing spot from the base of the cliff.
Assume that air resistance may be neglected, and g = 9.8 m/s².
The horizontal distance traveled in 2 seconds is
d = (1.8 m/s)*(2 s) = 3.6 m
The initial vertical velocity component is zero.
Therefore the vertical height traveled before landing on the water obeys the equation
h = (1/2)*(9.8 m/s²)*(2 s)² = 19.6 m
Answers:
The height of the cliff is 19.6 m
The distance of the landing spot from the base of the cliff is 3.6 m
14 you go up to 21 on cost and see what point is rhere or closest under in this case it is 14
Answer:11 tbs for 33 ounces of water
Step-by-step explanation:
Answer:
Both give - 6=5x
Step-by-step explanation:
First equation 2x-6=7x
When you solve it, it becomes :
2x-6=7x
Subtract 2x both sides
2x-2x-6=7x-2x=
-6=5x
2)5x-6=10
5x-5x-6=10x-5x
-6=5x