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3 years ago

Part C Factor the left side of the inequality by grouping

Mathematics

2 answers:

olga_2 [115]3 years ago

7 0

Answer:

Step-by-step explanation:

LUCKY_DIMON [66]3 years ago

3 0

Answer:

Hope this helps :)

Step-by-step explanation:

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Por favor que alguien me ayude con

Contact [7]

Este es el brainly ingles, no hables en español

(4/7).(-3/5) = (4.(-3))/(7.5) = -12/35

(3/5).(-6/7).(-4) = (3.(-6).(-4))/(5.7) = 72/35

6/(1/8) = 6.8 = 48

8 0

4 years ago

Lana is deciding whether to buy a pool pass for the summer. A pass costs $36.00 and

kirill115 [55]

Answer:

9 days

Step-by-step explanation:

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3 years ago

What is the difference between Experimental and Theoretical probability?

Alchen [17]

Answer: An experimental probability is based on past events, and a theoretical probability is based on analyzing what could happen. An experimental probability approaches a theoretical one when enough random samples are used.

6 0

4 years ago

The avrge amount of rainfalls is?

OLga [1]

Answer:

For the entire United States, excluding Hawaii and Alaska, the average amount of moisture falling as rain and snow is 30.21 inches

Step-by-step explanation:

depends on the state

7 0

3 years ago

If the circle has the same diameter as the edge length of the square, then the area of this circle is ___________the area of the

WINSTONCH [101]

Answer:

The area of this circle is $(\frac{\pi}{2} )$ the area of the square.

For the uniform electric field normal to the surface, the flux through the surface is electric field multiplied by the area of this surface.

Therefore, Φsquare is $(\frac{2}{\pi} )$ ϕcircle

Step-by-step explanation:

Area of the circle is given by;

$A_c = \frac{\pi d^2}{4}$

Area of the square is given by;

$A_s = L^2$

relationship between the edge length of the square, d, and length of its side, L,

$d = \sqrt{L^2 + L^2} \\\\d = \sqrt{2L^2}$

But area of the square , $A_s = L^2$

$d = \sqrt{2A_s}$

Then, the area of the square in terms of the edge length is given by;

$A_s = \frac{d^2}{2}$

Area of the circle in terms of area of the square is given by;

$A_c = \frac{\pi d^2}{4} = \frac{\pi}{2}(\frac{d^2}{2} )\\\\But \ A_s = \frac{d^2}{2} \\\\A_c = \frac{\pi}{2}(\frac{d^2}{2} )\\\\A_c = \frac{\pi}{2}(A_s )$

For the uniform electric field normal to the surface, the flux through the surface is electric field multiplied by the area of this surface.

Ф = E.A

Flux through the surface of the circle is given by;

$\phi _{circle} = E.(\frac{\pi d^2}{4})$

Flux through the surface of the square is given by;

$\phi _{square} = E.(\frac{d^2}{2} )\\\\\phi _{square} =E.(\frac{d^2}{2} ).(\frac{\pi}{2} ).(\frac{2}{\pi} )\\\\\phi _{square} =E.(\frac{\pi d^2}{4} ).(\frac{2}{\pi} )\\\\\phi _{square} =(\phi _{circle}).(\frac{2}{\pi} )$

Therefore, Φsquare is $(\frac{2}{\pi} )$ ϕcircle

5 0

4 years ago

Part C Factor the left side of the inequality by grouping￼￼

Part C Factor the left side of the inequality by grouping