A cereal box has dimensions of 2 in., 1 5 3 in., and 3 10 4 in.If the box contains 8 servings, how much volume does each serving
1 answer:
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Answer:
in one minute they rake leaves working together.
Step-by-step explanation:
If Maya rakes the leaves in x minutes, then, in one minute she rakes leaves.
In the case of Carla, if she rakes the leaves in y minutes, in one minute she rakes leaves.
Therefore, to know the portion of leaves they can rake in one minute working together, we need to sum up both of the portions each one of them rake in one minute, this gives us:
Now, to simplify this expression:
Thus, in one minute they rake leaves.
Answer:
C . 0.76
Step-by-step explanation:
We are given that on the first of each month , Shelly runs a 5 k race. She keeps track of her times to track her progress. Her time in minutes is recorded in the table:
Jan 40.55 Feb 41.51
March 42.01 Apr 38.76
May 36.32 June 34.28
July 35.38 Aug 37.48
Sept 40.87 Oct 48.32
Nov 41.59 Dec 42.71
We have to find the difference between the mean of the data , including the outlier and excluding the outlier
Outlier: That observation which is different from other observations.
The outlier in the given observations is 48.32 because is different from other observations.
Mean of the data including the outlier
Mean =
Mean=
Mean=
Mean=39.982
Mean of the data excluding the outlier
Mean=
Mean=39.224
Difference between mean of the data including the outlier and excluding the outlier=39.982-39.224=0.758
Difference between mean of the data including the outlier and excluding the outlier=0.76
Answer Answer:
Step-by-step explanation:
We are given that on the first of each month , Shelly runs a 5 k race. She keeps track of her times to track her progress. Her time in minutes is recorded in the table:
Jan 40.55 Feb 41.51
March 42.01 Apr 38.76
May 36.32 June 34.28
July 35.38 Aug 37.48
Sept 40.87 Oct 48.32
Nov 41.59 Dec 42.71
We have to find the difference between the mean of the data , including the outlier and excluding the outlier
Outlier: That observation which is different from other observations.
The outlier in the given observations is 48.32 because is different from other observations.
Mean of the data including the outlier
Mean =
Mean=
Mean=
Mean=39.982
Mean of the data excluding the outlier
Mean=
Mean=39.224
Difference between mean of the data including the outlier and excluding the outlier=39.982-39.224=0.758
Difference between mean of the data including the outlier and excluding the outlier=0.76
Answer :C . 0.76