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Rina8888 [55]
3 years ago
5

If 3 sinA+4 cosA=5 then prove that:sinA=3/5.​

Mathematics
1 answer:
lutik1710 [3]3 years ago
7 0

Answer:

Please check the explanation.

Step-by-step explanation:

Given the expression

3\:sinA+4\:cosA=5

\frac{4}{5}\:cosA=1-\frac{3}{5}sinA

Taking square on both sides

\left(\frac{4}{5}\:cosA\right)^2=\left(1-\frac{3}{5}sinA\right)^2

16\:Cos^2\:A\:=\:25\:+\:9\:Sin^2A\:-\:30\:Sin\:A

16\:-\:16\:Sin^2\:A\:=\:25\:+\:9\:Sin^2A\:-\:30\:Sin\:A

25\:Sin^2\:A\:\:-\:30\:Sin\:A\:+\:9\:=\:0

so the equation can further be easily solved

\sin \:A=\frac{3}{5}         ∵ sin A = [ 30 +- √(900 - 900) ] ÷ 50

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Alex73 [517]

Answer:

47.7

Step-by-step explanation:

length x width x height

6 x 3 x 2.65

5 0
3 years ago
When looking at the graph of a 5th degree function, how can you determine if all of the zeros of the function are real?
Finger [1]

Answer:

If it cuts x-axis 5 times.

Step-by-step explanation:

When we look at the graph of a function we can see its real roots by looking at its graph

The intersecting points that is the number of times a line cutting x-axis will be the real root of the function

So, by looking at the 5th degree function the number of time that function cuts x-axis will be the number of real roots.

So, if we need to say all the zeroes or roots of the function are real means it will cut the x-axis 5 times.

Because a function will have the root equal to its degree.

4 0
3 years ago
7 + 2y = 8x 3x - 2y = 0 Solve the system of equations by substitution. (70/3, 140/9) (7/5, 21/10) no solution coincident
Wittaler [7]
So we have the system of equations:
7+2y=8x equation (1)
3x-2y=0 equation (2)

To use substitution, we are going to solve for one variable in one of our equations, and then we are going to replace that value in the other equation:
Solving for x in equation (2):
3x-2y=0
3x=2y
x= \frac{2}{3}y equation (3)

Replacing equation (3) in equation (1):
7+2y=8x
7+2y=8( \frac{2}{3} y)
7+2y= \frac{16}{3} y
7= \frac{10}{3} y
y= \frac{7}{ \frac{10}{3} }
y= \frac{21}{10} equation (4)

Replacing equation (4) in equation (3):
x= \frac{2}{3}y
x=( \frac{2}{3} )( \frac{21}{10} )
x= \frac{7}{5}

We can conclude that the solution of our system of equations is <span>(7/5, 21/10)</span>
5 0
3 years ago
-1/6 + ( -3/7) = <br><br> A. -25/42<br> B. -4/13<br> C. 11/42<br> D. 2/13
alekssr [168]

Answer: the anwser is A

Step-by-step explanation:

I used a calculator lol

6 0
3 years ago
Read 2 more answers
Please help me with this.
OLga [1]

Swapping rows alters the sign of the determinant:

\begin{vmatrix} x & y & z \\ -8 & 2 & -12 \\ u & v & w \end{vmatrix} = - \begin{vmatrix} x & y & z \\ u & v & w \\ -8 & 2 & -12 \end{vmatrix}

Multiplying a single row by a scalar scales the determinant by the same amount:

\begin{vmatrix} x & y & z \\ u & v & w \\ -8 & 2 & -12 \end{vmatrix} = -2 \begin{vmatrix} x & y & z \\ u & v & w \\ 4 & -1 & 6 \end{vmatrix}

Then

\begin{vmatrix} x & y & z \\ -8 & 2 & -12 \\ u & v & w \end{vmatrix} = -(-2) \begin{vmatrix} x & y & z \\ u & v & w \\ 4 & -1 & 6 \end{vmatrix} = 2\times(-6) = \boxed{-12}

8 0
2 years ago
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