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3 years ago

God loves you!!!!!!!!!

Mathematics

2 answers:

jok3333 [9.3K]3 years ago

4 0

Answer:

thank you ^-^

Step-by-step explanation:

you too :)

BabaBlast [244]3 years ago

4 0

Answer:

He loves you too!!

Step-by-step explanation:

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Which of the following is not a triangle congruence theorem?<br><br> ASA<br> AAS<br> SSA

iogann1982 [59]

The answer is SSA, that what I found

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3 years ago

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If I get paid every two weeks and I work 5 days every week I get paid 7.25 and work ten hours each day how much will my check be

Svetradugi [14.3K]

The total is 362.5 every two weeks

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4 years ago

Given that f.x 3x-2 over x+1 g[x] x +5 evaluate f[-4] and gf [-2]

Jobisdone [24]

The value of f[ -4 ] and g°f[-2] are $\frac{14}{3}$ and 13 respectively.

<h3>What is the value of f[-4] and g°f[-2]?</h3>

Given the function;

$f(x) = \frac{3x-2}{x+1}$
$g(x)=x+5$
f[ -4 ] = ?
g°f[ -2 ] = ?

For f[ -4 ], we substitute -4 for every variable x in the function.

$f(x) = \frac{3x-2}{x+1}\\\\f(-4) = \frac{3(-4)-2}{(-4)+1}\\\\f(-4) = \frac{-12-2}{-4+1}\\\\f(-4) = \frac{-14}{-3}\\\\f(-4) = \frac{14}{3}$

For g°f[-2]

g°f[-2] is expressed as g(f(-2))

$g(\frac{3x-2}{x+1}) = (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) = \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) = \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) = \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) = \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) = \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) = \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) = 13$

Therefore, the value of f[ -4 ] and g°f[-2] are $\frac{14}{3}$ and 13 respectively.

Learn more about composite functions here: brainly.com/question/20379727

#SPJ1

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2 years ago

What is x cubed in standard form

Gelneren [198K]

Answer:

x^3

Step-by-step explanation:

It stays the same.

Hope this helps.

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4 years ago

(05.02 MC) A system of equations is shown below: 4x = −3y + 17 3x − 4y = −6 What is the solution to this system of equations? (−

aliina [53]

4x=-3y+17 becomes 4x+3y=17

4x+3y=17
3x-4y=-6

alrighty

elimination

muliply first equation by 4 and 2nd by 3 and add them
16x+12y=68
9x-12y=-18
add them

25x+0y=50
25x=50
idivide both sides by 25
x=2

sub back

3x-4y=-6
3(2)-4y=-6
6-4y=-6
-4y=-12
y=3

(x,y)
(2,3)

5 0

4 years ago

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