3 years ago

What are two different common denominators for 1/2 and 1/14

Mathematics

1 answer:

makkiz [27]3 years ago

8 0

Answer:

Step-by-step explanation:

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AveGali [126]

The simplified expression of $$4 x \cdot \frac{1}{x^{-5}} \cdot x^{-3}$ is $4x^3$ .

Solution:

Given expression is $4 x \cdot \frac{1}{x^{-5}} \cdot x^{-3}$ .

To simplify the given expression.

$$\Rightarrow4 x \cdot \frac{1}{x^{-5}} \cdot x^{-3}$

Using exponent rule: $\frac{1}{a^{-m}}=a^m$

$$\Rightarrow4x \cdot x^{5}.x^{-3}$

Using another exponent rule: $a^m \cdot a^n=a^{m+n}$

$$\Rightarrow4x \cdot x^{5-3}$

$$\Rightarrow4x \cdot x^{2}$

Using exponent rule: $a^m \cdot a^n=a^{m+n}$

$$\Rightarrow4x^{1+2}$

$$\Rightarrow4x^3$

Hence the simplified expression of $$4 x \cdot \frac{1}{x^{-5}} \cdot x^{-3}$ is $4x^3$ .

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3 years ago