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3 years ago

Factor x^2 + 5x - 50

Mathematics

1 answer:

Varvara68 [4.7K]3 years ago

5 0

(using the AC Method) (x - 5) (x + 10)

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Michael started a saving account with $300.after 4 weeks, he had $350,and after 9 weeks , he had $400 what is the rate of change

Arisa [49]

(400-350)/(9-4)=50/5=10 per week

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3 years ago

Give an example of a function with both a removable and a non-removable discontinuity.

navik [9.2K]

Answer:

(x+5)(x-3) / (x+5)(x+1)

Step-by-step explanation:

A removeable discontinuity is always found in the denominator of a rational function and is one that can be reduced away with an identical term in the numerator. It is still, however, a problem because it causes the denominator to equal 0 if filled in with the necessary value of x. In my function above, the terms (x + 5) in the numerator and denominator can cancel each other out, leaving a hole in your graph at -5 since x doesn't exist at -5, but the x + 1 doesn't have anything to cancel out with, so this will present as a vertical asymptote in your graph at x = -1, a nonremoveable discontinuity.

8 0

3 years ago

whats the equation for the perpendicular bisector of the line segment whose endpoints are (-5,3) and (3,7)?

riadik2000 [5.3K]

Answer:

The equation of perpendicular bisector of the line segment passing through (-5,3) and (3,7) is: $y = -2x+3$

Step-by-step explanation:

Given points are:

(-5,3) and (3,7)

The perpendicular bisector of line segment formed by given points will pass through the mid-point of the line segment.

First of all we have to find the slope and mid-point of given line

Here

(x1,y1) = (-5,3)

(x2,y2) = (3,7)

The slope will be:

$m = \frac{y_2-y_1}{x_2-x_1}\\m = \frac{7-3}{3+5}\\m = \frac{4}{8}\\m = \frac{1}{2}$

The mid-point will be:

$(x,y) = (\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2})\\ = (\frac{-5+3}{2},\frac{3+7}{2})\\= (\frac{-2}{2},\frac{10}{2})\\=(-1,5)$

Let m1 be the slope of the perpendicular bisector

Then using, "Product of slopes of perpendicular lines is -1"

$m.m_1 = -1\\\frac{1}{2}.m_1 = -1\\m_1 = -1*2\\m_1 = -2$

We have to find the equation of a line with slope -2 and passing through (-1,5)

The slope-intercept form is given by:

$y = mx+b\\y = -2x+b$

Putting the point (-1,5) in the equation

$5 = -2(-1)+b\\5 = 2+b\\b = 5-2\\b = 3$

The final equation is:

$y = -2x+3$

Hence,

The equation of perpendicular bisector of the line segment passing through (-5,3) and (3,7) is: $y = -2x+3$

4 0

3 years ago

Find the value of y.

lisabon 2012 [21]

10
Below is how I did it

4 0

3 years ago

15℅ of 6th grade teachers give homework over the holiday break. If 12 teachers give homework, how many total 6th grade teachers

hoa [83]

Answer:

Step-by-step explanation:

Its a trick question, 15% of 6th grade teachers give HW, but there are 12 teachers. its not gonna be 15% of 12, because you would also get a fraction of a teacher.

4 0

3 years ago