Answer:
(x+5)(x-3) / (x+5)(x+1)
Step-by-step explanation:
A removeable discontinuity is always found in the denominator of a rational function and is one that can be reduced away with an identical term in the numerator. It is still, however, a problem because it causes the denominator to equal 0 if filled in with the necessary value of x. In my function above, the terms (x + 5) in the numerator and denominator can cancel each other out, leaving a hole in your graph at -5 since x doesn't exist at -5, but the x + 1 doesn't have anything to cancel out with, so this will present as a vertical asymptote in your graph at x = -1, a nonremoveable discontinuity.
Answer:
The equation of perpendicular bisector of the line segment passing through (-5,3) and (3,7) is: 
Step-by-step explanation:
Given points are:
(-5,3) and (3,7)
The perpendicular bisector of line segment formed by given points will pass through the mid-point of the line segment.
First of all we have to find the slope and mid-point of given line
Here
(x1,y1) = (-5,3)
(x2,y2) = (3,7)
The slope will be:

The mid-point will be:

Let m1 be the slope of the perpendicular bisector
Then using, "Product of slopes of perpendicular lines is -1"

We have to find the equation of a line with slope -2 and passing through (-1,5)
The slope-intercept form is given by:

Putting the point (-1,5) in the equation

The final equation is:

Hence,
The equation of perpendicular bisector of the line segment passing through (-5,3) and (3,7) is: 
Answer:
12
Step-by-step explanation:
Its a trick question, 15% of 6th grade teachers give HW, but there are 12 teachers. its not gonna be 15% of 12, because you would also get a fraction of a teacher.