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3 years ago

Find (f∘g)(x). f(x)=5x+1 g(x)=2x Write your answer as a polynomial in simplest form.

Mathematics

1 answer:

vladimir2022 [97]3 years ago

4 0

(f o g)=f(g(x))
just sub
f(g(x))
sub g(x) for x in f(x)
g(x)=2x
2x=x in f(x)
f(g(x)=f(2x)=5(2x)+1=10x+1

(f o g)=10x+1

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The table shows a gym class's average results for boys and

Rufina [12.5K]

Susan can jump at most 104 in during the long jump

<h3>Inequality</h3>

Inequality is an expression that show the non equal comparison of two or more variables and numbers.

From the table, the average result for females = 8ft 4in = (8 * 12)in + 4in = 100 in

Since Susan could jump no farther than 4 inches more than the average distance for females, hence:

j ≤ 4 + 100

j ≤ 104 in

Susan can jump at most 104 in during the long jump

Find out more o Inequality at: brainly.com/question/24372553

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2 years ago

PLEASE HELP !! ILL GIVE BRAINLIEST !!

AveGali [126]

Answer:

Angles and XWY and STR

Step-by-step explanation:

These two angels are alternate exterior angels because:

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2 years ago

Y=-x^2+2x+10 y=x+2 Substitution Please show your work Need ASAP

erik [133]

Answer:

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

Step-by-step explanation:

we have

$y=-x^{2} +2x+10$ ----> equation A

$y=x+2$ ----> equation B

Solve the system by substitution

substitute equation B in equation A

$x+2=-x^{2} +2x+10$

solve for x

$-x^{2} +2x+10-x-2=0$

$-x^{2} +x+8=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-x^{2} +x+8=0$

$a=-1\\b=1\\c=8$

substitute in the formula

$x=\frac{-1\pm\sqrt{1^{2}-4(-1)(8)}} {2(-1)}$

$x=\frac{-1\pm\sqrt{33}} {-2}$

$x=\frac{-1+\sqrt{33}} {-2}$ -----> $x=\frac{1-\sqrt{33}} {2}$

$x=\frac{-1-\sqrt{33}} {-2}$ -----> $x=\frac{1+\sqrt{33}} {2}$

Find the values of y

For $x=\frac{1-\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1-\sqrt{33}} {2}+2$ ----> $y=\frac{5-\sqrt{33}} {2}$

For $x=\frac{1+\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1+\sqrt{33}} {2}+2$ ----> $y=\frac{5+\sqrt{33}} {2}$

therefore

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

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2 years ago

What is a cereal box an example of

lesya [120]

Answer:

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Step-by-step explanation:

it has a title,subheading,and more

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2 years ago

Read 2 more answers

Which of the following is equal to (3^-3)(3^7)? 3 ^-10 3 ^10 3 ^4 3 ^-4

bixtya [17]

Answer:

3⁴

Step-by-step explanation:

Hey there! To evaluate $\displaystyle \large{3^{-3} \cdot 3^7}$ , we can simply do by using one of exponent laws.

Laws of Exponent

$\displaystyle \large{a^m \cdot a^n = a^{m+n}}$

Hence, let m = -3 and n = 7. Therefore, $\displaystyle \large{3^{-3} \cdot 3^7 = 3^{-3+7} \to 3^4}$

Let me know if you have any questions regarding the exponent!

7 0

2 years ago