The point that the graphs of f and g have in common are (1,0)
<h3>How to get the points?</h3>
The given functions are:
f(x) = log₂x
and
g(x) = log₁₀x
We know that logarithm of 1 is always zero.
This means that irrespective of the base, the y-values of both functions will be equal to 0 at x=1
Therefore the point the graphs of f and g have in common is (1,0).
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Answer:
14.4222
Step-by-step explanation:
Distance between two points = √(x₂ – x₁)² + (y₂ – y₁)²
Distance between two points = √(6 – -2)² + (-5 – 7)²
√(6 – -2)² + (-5 – 7)²
√8² + (-12)²
√64 + 144
√208
14.4222
I hope this helps
The solution of the system of equations that is given is (2,-1).
Given a system of equations are 5x+y=9 and 3x+2y=4.
A system of linear equations (or linear system) is a collection of one or more linear equations involving the same variables. A solution to a linear system is an assignment of values to the variables such that all the equations are simultaneously satisfied.
The given equations are
5x+y=9 ......(1)
3x+2y=4 ......(2)
Here, the substitution method is used to solve the system of equations.
Find the value of y from equation (1) by subtracting 5x from both sides.
5x+y-5x=9-5x
y=9-5x
To find the value of x substitute the value of y in equation (2).
3x+2(9-5x)=4
Apply the distributive property a(b+c)=ab+ac as
3x+2×9-2×5x=4
3x+18-10x=4
Combine the like terms on the left side as
-7x+18=4
Subtract 18 from both sides and get
-7x+18-18=4-18
-7x=-14
Divide both sides by -7 and get
(-7x)÷(-7)=(-14)÷(-7)
x=2
Substitute the value of x in equation (1) and get
5(2)+y=9
10+y=9
Subtract 10 from both sides
10+y-10=9-10
y=-1
Hence, the solution of system of equations 5x+y=9 and 3x+2y=4 is (2,-1).
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4y-8>10
Add 8
4y-8+8>10+8
4y>18
Now divide both sides by 4
4y/4 > 18/4
y>9/2
Now let's see if it will be true
Replace y by its value
4(9/2)-8>10
36/2 -8 > 10
18-8 > 10
10 > 10
That's false because 10 can not smaller than 10
so it should be = instead
Answer : False
I hope that's help:)
