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3 years ago

What is the area of the surface cone rounded to the nearest tenth?

Mathematics

1 answer:

EleoNora [17]3 years ago

4 0

Answer:

A = 422.4

i promise it's right :)

You might be interested in

If the circumference of a circle is 84.5 ft, find the radius.

Elina [12.6K]

Answer:

13.448, rounded off: 13.5 ft

Step-by-step explanation:

$r=\frac{C}{2\pi }$

Where r = radius, C = circumference.

$r=\frac{84.5}{2\pi } =13.448$ = 13.5 ft

6 0

3 years ago

Read 2 more answers

Help please please help ASAP * please don’t answer if you don’t know

Julli [10]

Answer:

Your answer is x = 24 , y =8√3

Step-by-step explanation:

Sorry for late answer actually I was preparing for my exams. ❤

3 0

3 years ago

Help Please!!!!!!!!!!

LenKa [72]

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

$x+3y\leq 6$

Isolate the variable y

$3y\leq 6-x$

$y\leq 2-(1/3)x$

The solution is the shaded area below the solid line

Is below because the symbol of the inequality is less

Is a solid line because the line is included in the solution

The equation of the solid line is $y=2-(1/3)x$

To graph the solution find the intercepts

Find the x-intercept (value of x when the value of y is equal to zero)

For y=0, x=6 --------> point (6,0)

Find the y-intercept (value of y when the value of x is equal to zero)

For x=0, y=2 -------> point (0,2)

Graph the inequality

see the attached figure

5 0

3 years ago

A square piece of fabric has an area of 16x^2+40x+25 square inches. The length of each side of the fabric is cx+d, where c and d

lozanna [386]

$A=(cx+d)^2=c^2x^2+2cdx+d^2\\\\c^2x^2+2xcd+d^2=16x^2+40x+25\\\Downarrow\\c^2=16;\ 2cd=40;\ d^2=25\\\Downarrow\\c=\sqrt{16};\ cd=20;\ d=\sqrt{25}\\\Downarrow\\\boxed{c=4\ and\ d=5}\\\\The\ length\ of\ side:cx+d=\boxed{4x+5}\\\\The\ perimeter\ of\ the\ piece\ of\ fabric:4(4x+5)=\boxed{16x+20}\\\\For\ x=2:\\16\cdot2+20=32+20=\boxed{52}$