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AVprozaik [17]
3 years ago
9

Which units of pressure are equivalent and require no conversion of the value

Chemistry
1 answer:
Romashka [77]3 years ago
8 0
1pa=1N/m^2
1atm=760mmHg
1mmHg=1torr
1atm=101.325pa
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The following diagram shows a common way that scientific knowledge is discovered.
vesna_86 [32]
The common way the scientific knowledge is discovered passes through several steps:
First you observe the phenomenon around you. Then you develop a certain hypothesis based on your observation. After that you start testing your hypothesis and collecting the resultant data from your tests.
Finally comes the conclusion of whether your hypothesis is accepted or rejected. 
If it is accepted, it can further develop into a theory and a publication afterwards.

The answer is: hypothesis
6 0
3 years ago
Read 2 more answers
What is the rate of the reaction when the initial concentration of no is 0.400 m and that of br2 is 0.245 m ?
Hoochie [10]
If the final concentration of NOBr = 0.250M
Change in concentration of NOBr = +0.250 M
Change in concentration of NO = -0.250 M
Change is concentration of Br2 = -0.125 M ( since number of moles of Br2 is 0.5 times the number of mole of NOBr)
Final concentration of NO = 0.400-0.250 = 0.150 M
Final concentration of Br2 = 0.245 - 0.125 M = 0.0120 M
Therefore;
Kc = conc (NOBr)^2/ ((conc NO)^2 ×(conc (Br2)
     = (0.250²)/(0.150²×0.120)
      = 23.148
      = 23.1 mol/dm³
8 0
3 years ago
What body of water has the largest tidal range in meters
Artist 52 [7]
The worlds largest tidal range is 16.3 meters and it occurs in Bay of Fundy, Canada
6 0
3 years ago
How many atoms of oxygen are present in 7.51 grams of<br> glycine with formula C₂H5O2N?
Blizzard [7]

1.205 × 10²³ atoms of oxygen will be present in 7.51 grams of glycine with formula C₂H5O2N. Details about number of atoms can be found below.

How to calculate number of atoms?

The number of atoms of a substance can be calculated by multiplying the number of moles of the substance by Avogadro's number.

However, the number of moles of oxygen in glycine can be calculated using the following expression:

Molar mass of C₂H5O2N = 75.07g/mol

Mass of oxygen in glycine = 32g/mol

Hence; 32/75.07 × 7.51 = 3.2grams of oxygen in glycine

Moles of oxygen = 3.2g ÷ 16g/mol = 0.2moles

Number of atoms of oxygen = 0.2 × 6.02 × 10²³ = 1.205 × 10²³ atoms

Therefore, 1.205 × 10²³ atoms of oxygen will be present in 7.51 grams of glycine with formula C₂H5O2N.

Learn more about number of atoms at: brainly.com/question/8834373

#SPJ1

3 0
2 years ago
chinua reacts 37g of magnesium with 150g of sulfuric acid. what will be the total mass of the products of this reaction
Andreas93 [3]

the total mass is 187g. The total mass of the reactant is always equal to total mass of the products.

explanation:

as per the given details, the reactant involved in the reaction are 37g of magnesium and 150g of sulfuric acid . the total of the reactant is 187g.

7 0
2 years ago
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