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Paul [167]
3 years ago
5

A group of experimenters has 30 hummingbirds in a large container and needs to assign 10 to each of the three groups labeled A,

B, and C for an experiment. They can capture the hummingbirds one at a time when the hummingbirds enter a side chamber in the container that is baited with food. Which of the following methods is most likely to result in three comparable groups of 10 hummingbirds each?
SAT
2 answers:
aleksley [76]3 years ago
8 0

Answer:

E.) Place each hummingbird in its own numbered container (numbered from 1–30) in the order that it was caught. Write the numbers from 1 to 30 on slips of paper, put the slips in a jar, and mix them well. Pick 10 numbers out of the jar. Assign the hummingbirds in the containers with those numbers to group A. Pick 10 more numbers for group B. Assign the remaining hummingbirds to group C.

Explanation:

This is the only method that provides truely random results. Using Simple Random Sampling.

A.) This is wrong because it uses a convenience sample

B.) Wrong because it involves you picking out which birds to assign to each group (Leading to bias)

C.) Rolling an even number isn't a good way to get random results.

D.) Again, rolling a dice isnt the best way to get random results.

E. Correct since it is the only answer that uses a proven method to get random results (Simple Random Sampling)

Montano1993 [528]3 years ago
6 0

Answer:

answer should be D

Explanation:

Place each hummingbird in its own numbered container in order that it was caught. write the numbers 1 to 30 on the slips of paper, put the slips in a jar and mix them well.

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A pedestrian may walk against traffic (on the left side of the road), if there aren't sidewalks.

<h3>What is a traffic rule?</h3>

A traffic rule can be defined as an accepted and enforceable law or guideline established by a road safety agency, so as to give warnings and instructions to road users such as:

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Read more on traffic rules here: brainly.com/question/22768531

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mrs_skeptik [129]
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Suppose that grade point averages of undergraduate students at one university have a bell-shaped distribution with a mean of 2.6
olga2289 [7]

Answer:

  • <em><u>97.5% of the students have grade point averages that are at least 3.4</u></em>

Explanation:

<u>1. Find how many standard deviations is 3.4 from the mean, 2.62</u>

      z-score=\frac{x-mean}{standard\text{ }deviation}

        z-score=(3.4-2.62)/0.39=2

<u></u>

<u>2. Apply the empirical rule</u>

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We calculated that 3.4 is 2 standard deviations from the mean.

Since 95% of the data are within 2 standard deviations from the mean, 5% of the data are out of the 2 standard deviations region; half of that (2.5%) are abovethe mean + 2 standard deviations

Hence, the grade point averages of 95% + 2.5% of the students are below the mean plus two standard deviations, and you can say that that is the percentage of students whose grade point averages are at least 3.4.

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Answer:

A  or B could be right, but I’m leaning towards B

Explanation:

8 0
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