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3 years ago

Uehehejjdjdjejjejejjdjdjejejejejejjejejejeejjd

Mathematics

2 answers:

Serhud [2]3 years ago

8 0

Answer:

kgkbfkbfbk3grrkmfbhrfikrk

Len [333]3 years ago

6 0

Answer:

thank you for the free point i guess

Step-by-step explanation:

can u mark me brainlest plz

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Explain the difference between f(2) and f(x) = 2. Use a verbal explanation and create examples to make it very clear. Please hel

Firlakuza [10]

Let x be a variable, and f(x) a function of that variable.

f(2) is a <em>number </em>; it's the value of the function f(x) when x = 2, assuming that value exists.

f(x) = 2 is a <em>statement </em>; it says there is some value of x for which the function returns a value of 2. Because it's a statement, it can be true or false.

Here's an example:

Define f(x) = sin(x). Then f(2) = sin(2) ≈ 0.909297.

If x is a real number, then the statement sin(x) = 2 is false, because -1 ≤ sin(x) ≤ 1 for all real x.

If we replace 2 with 1, on the other hand, we get

f(1) = sin(1) ≈ 0.84147

and

sin(x) = 1 ==> x = π/2 + 2nπ

where n is any integer. (So we're talking about numbers like π/2, -3π/2, 5π/2, -7π/2, and so on.) We're saying here that any real number x of the above form satisfies the equation and makes the statement true.

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3 years ago

A magazine conducts an annual survey in which readers rate their favorite cruise ship. All ships are rated on a 100-point scale,

Lyrx [107]

Answer:

a) The point of estimate for $\mu_1 -\mu_2$ is just given by:

$\bar X_1 -\bar X_2 =85.82-81.90=3.92$

b) $SE=\sqrt{(\frac{4.55^2}{35}+\frac{3.97^2}{44})}=0.975$

And the Margin of error is given by:

$Me= z_{\alpha/2} * SE=1.96*0.975=1.910$

c) The 95% confidence interval would be given by $2.009 \leq \mu_1 -\mu_2 \leq 5.83$ .

Step-by-step explanation:

Notation and previous concepts

$n_1 =35$ represent the sample of ships that carry fewer than 500 passengers

$n_2 =44$ represent the sample of ships that carry 500 or more passengers

$\bar x_1 =85.82$ represent the mean sample of of ships that carry fewer than 500 passengers

$\bar x_2 =81.90$ represent the mean sample of of ships that carry 500 or more passengers

$\sigma_1 =4.55$ represent the population deviation of ships that carry fewer than 500 passengers

$\sigma_2 =3.97$ represent the sample deviation of ships that carry 500 or more passengers

$\alpha=0.05$ represent the significance level

Confidence =95% or 0.95

The confidence interval for the difference of means is given by the following formula:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2}\sqrt{(\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2})}$ (1)

Part a

The point of estimate for $\mu_1 -\mu_2$ is just given by:

$\bar X_1 -\bar X_2 =85.82-81.90=3.92$

Part b: At 95% confidence, what is the margin of error?

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$