2 years ago

Answer quick please.

Mathematics

1 answer:

Brilliant_brown [7]2 years ago

4 0

Answer

The Answer is A C D

Step-by-step explanation:

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3 years ago

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Convert to the product of multiplication a^2-b^2-4b-4

kirill [66]

$a^2-b^2-4b-4$ in form of multiplication is $(a-b)(a+b)-4(b+1)$ .

Step-by-step explanation:

We know that factors are the numbers that are being multiplied together . As 6532*7 = 45724 .Here 6532 & 7 are the factors and 45724 is product of the factors .

Here , we need to convert to the product of multiplication

a^2-b^2-4b-4 or , $a^2-b^2-4b-4$ :

⇒ $a^2-b^2-4b-4$

We know by identity that , $p^2-q^2 = (p-q)(p+q)$

⇒ $(a-b)(a+b)-4b-4$

Taking common term out as -4 :

⇒ $(a-b)(a+b)-4(b+1)$

Therefore , $a^2-b^2-4b-4$ in form of multiplication is $(a-b)(a+b)-4(b+1)$ .

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2 years ago

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Step-by-step explanation:

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Match each expression to its equivalent standard form

pogonyaev

Move the first one to the bottom,then the second to the top ans you will know where to put the rest

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