Question

10 in. 9 in. 11 in. help please!!!

Answer 1

$\pink{\boxed{\rm Answer + Explain}}$

.

Area of parallelogram

$\rm L = base \times hight$

$\rm L = 11 \times 9$

$\blue{\boxed{\rm L = 99 {in}^{2}}}$

.

around of parallelogram

$\rm = (2 \times base) + (2 \times side)$

$\rm = (2 \times 11) + (2 \times 10)$

$\rm = 22 + 20$

$\blue{\boxed{ \rm = 42 in }}$