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natta225 [31]
3 years ago
5

Solve the following system of equations graphically on the set of axes below. y=3x−3 , x+y=5

Mathematics
1 answer:
topjm [15]3 years ago
6 0

Answer:

x=2, y=3

Step-by-step explanation:

First, graph both equations on a rectangular coordinate system (see attached screenshot). Then, simply figure out where these two lines intersect. Since they intersect at (2,3), x=2 and y=3.

Plugging these values in the equations for x and y, you can see if these are the correct answers:

(3)=3(2)-3, (2)+(3)=5

Since both of these are true, you have the right answer.

Hope this helps!

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A student has taken three math tests so far this semester His scores for the first three tests were 76, 80, and 84
Charra [1.4K]

Answer:

A=96%         B=86%

Step-by-step explanation:

brainlist will be welcomed :))

8 0
3 years ago
33, 25, 42, 25, 31, 37, 46,29,38<br>What is the first quartile of the data?​
NISA [10]
answer:
Step by step solution:
1) put the numbers in order:
25,25,29,31,33,37,38,42,46
2) find the median:
25,25,29,31,33,37,38,42,46
33
3) find the median of the first quartile:
25,25,29,31
25 and 29
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6 0
3 years ago
PLEASE HELP!!! 15 POINTS!!
tankabanditka [31]

Answer:

23.4 cm

Step-by-step explanation:

If the base of the triangle is half of that of a given side, then we need to divide the given side by 2 to get the base.

46.8

---------2

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There is your answer

Hope it helped

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7 0
3 years ago
Read 2 more answers
Which shows the most reasonable way to estimate 3 and StartFraction 4 over 7 EndFraction (Negative 2 and StartFraction 1 over 12
geniusboy [140]

Answer:

it's b

Step-by-step explanation:

7 0
2 years ago
Anyone know the answer?? ​
Serggg [28]

Answer:

the second option

Step-by-step explanation:

in ax²+bx+c = 0:

x = \frac{-b+-\sqrt{b^2-4ac} }{2a}

subtract both sides by 6 to get to this form, as the right side will be left with 0

6x² + 8x - 6 = 0

here, the coefficient for x² (a) is 6, the coefficient for x (b) is 8, and the remaining number added on (c) is -6

plugging our numbers into the formula, we get

x = \frac{-8+-\sqrt{(-8)^2-4(6)(-6)} }{2(6)}\\= \frac{-8+-\sqrt{64-(-144)} }{12} \\= \frac{-8+-\sqrt{208} }{12} \\ = \frac{-8+\sqrt{208} }{12} or \frac{-8-\sqrt{208} }{12}\\= 0.53518375848 or -1.86851709182\\= approximately -1.87, 0.54

8 0
2 years ago
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