E.
Fractions are just division.
In order for her to find the number of stars she needs to divide to find out how many she needs.
Answer:
The original area would be multiplied by the scale factor of 2² to get the new area.
Step-by-step explanation:
If you double the radius lets so lets do an example
(a=πr²) so
if x is the radius the area would be x²π
double the radius so 2x then the area would be
(2x)²π so 4x²π
4x²π/x²π= 4 so its 4 times greater or
D the last answer or The original area would be multiplied by the scale factor of 2² to get the new area.
Answer:
37.36%
Step-by-step explanation:
Each year it increases 1.6%.
So year 1 it increases (1+1.6%), year 2 increases (1+1.6%)^2 and so on...
so after 20 years, overall increase is found by 1.016^20 = 1.3736 or increase of 37.36%
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The domain of f/g
consists of numbers x for which g(x) cannot equal 0 that are in the domains of
both f and g.
Let’s take this equation as an example:
If f(x) = 3x - 5 and g(x)
= square root of x-5, what is the domain of (f/g)x.
For x to be in the domain of (f/g)(x), it must be
in the domain of f and in the domain of g since (f/g)(x) = f(x)/g(x). We also
need to ensure that g(x) is not zero since f(x) is divided by g(x). Therefore,
there are 3 conditions.
x must be in the domain of f:
f(x) = 3x -5 are in the domain of x and all real numbers x.
x must be in the domain of g:
g(x) = √(x - 5) so x - 5 ≥ 0 so x ≥ 5.
g(x) can not be 0: g(x)
= √(x - 5) and √(x - 5) = 0 gives x = 5 so x ≠ 5.
Hence to x x ≥ 5 and x ≠ 5
so the domain of (f/g)(x) is all x satisfying x > 5.
Thus, satisfying <span>satisfy all
three conditions, x x ≥ 5 and x ≠ 5 so the domain of (f/g)(x) is all x
satisfying x > 5.</span>
The correct answer is right.
An acute one would have all three acute, while an obtuse one would have at least one obtuse angle.
