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natta225 [31]
3 years ago
5

Solve the following system of equations graphically on the set of axes below. y=3x−3 , x+y=5

Mathematics
1 answer:
topjm [15]3 years ago
6 0

Answer:

x=2, y=3

Step-by-step explanation:

First, graph both equations on a rectangular coordinate system (see attached screenshot). Then, simply figure out where these two lines intersect. Since they intersect at (2,3), x=2 and y=3.

Plugging these values in the equations for x and y, you can see if these are the correct answers:

(3)=3(2)-3, (2)+(3)=5

Since both of these are true, you have the right answer.

Hope this helps!

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Use the spinner to determine the probability of each outcome type your answers as fractions in simplest form. Fractions should b
DaniilM [7]

Answer:

Probability of spinning a 1 is 25 percent.

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Probability of spinning a 5 is 0 percent

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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find the solution by graphing the equations pls help
lilavasa [31]

Answer:

graph these
y = 2x + 2
y = 2x - 3

Step-by-step explanation:

2x - y = -2
2x - y = 3

convert to y intercept form
first
2x - y = -2
-y = -2x - 2
y = 2x + 2
second
2x - y = 3
-y = -2x + 3
y = 2x - 3

you are left with
y = 2x + 2
y = 2x - 3
i cannot graph these for you, but i assume you know how, there is no solution because the lines are parallel

4 0
2 years ago
The change of rate is
irakobra [83]

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Hope this helps!

5 0
3 years ago
A village fete has a children’s running race each year, run in heats of up to ten children. For each heat the first three contes
bekas [8.4K]

Answer:  1) 1/3,654     2) 3/406     3) 72,684,900,288,000      4) 120

<u>Step-by-step explanation:</u>

1)         First       and        Second         and         Third

  \dfrac{3\ total\ prizes}{29\ total\ people}\times \dfrac{2\ remaining\ prizes}{28\ remaining\ people}\times \dfrac{1\ remaining\ prize}{27\ remaining\ people}=\dfrac{6}{21,924}\\\\\\.\qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \quad =\large\boxed{\dfrac{1}{3,654}}

2)         First       and          Second

   \dfrac{3\ total\ prizes}{29\ total\ people}\times \dfrac{2\ remaining\ prizes}{28\ remaining\ people}=\dfrac{6}{812}=\large\boxed{\dfrac{13}{406}}

3)\quad \dfrac{29!}{(29-10)!}=\large\boxed{72,684,900,288,000}

4)\quad _{10}C_3=\dfrac{10!}{3!(10-3)!}=\large\boxed{120}

8 0
3 years ago
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IRINA_888 [86]

Answer:

Part A: hx2=a

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Step-by-step explanation:

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