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3 years ago

surface area of a cylinder with a radius of 8 centimeters and height of 10 centimeters? express the answer in hundredths.

Mathematics

1 answer:

satela [25.4K]3 years ago

7 0

Answer:

A≈904.78cm²

Step-by-step explanation:

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Andy is building a model of a square pyramid for a class project. The side length of the square base is 11 inches and the slant

zvonat [6]

Answer:

The answer is 792.

Step-by-step explanation:

I got the answer by first imagining how the 3d shape looks ike. Since one of the sqaure base length is 11 I found the base surface area by doing 11 times 11.My answer was 132. The since one of the slant length of the pyramid's triangle is 15, I did 11 times 15, my answer was 165. There are four triangles in the pyramid so I did 165 times 4, my answer was 660.

All the triangle surface area is 660 plus the sqaure surface are which is 132, that gave me my answer 792.

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3 years ago

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gladu [14]

Answer:

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Step-by-step explanation:

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2 years ago

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3 years ago

15.eye color if 2/3 of the girls in class have Brown eyes and 1/4 of the girls have blue eyes what fraction of the girls in clas

Rina8888 [55]

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3 years ago

A large fish tank at an aquarium needs to be emptied so that it can be cleaned. When its

VikaD [51]

Answer:

The draining time when only the big drain is opened is 2.303 hours.

The draining time when only the small drain is opened is 5.303 hours.

Step-by-step explanation:

From Physics, we know that volume flow rate ( $\dot V$ ), measured in liters per hour, is directly proportional to draining time ( $t$ ), measured in hours. That is:

$\dot V \propto \frac{1}{t}$

$\dot V = \frac{k}{t}$ (Eq. 1)

Where $k$ is the proportionality constant, measured in liters.

From statement, we have the following three expressions:

(i) Large and small drains are opened

$\dot V_{s}+\dot V_{l} = \frac{k}{2}$ (Eq. 2)

$\frac{\dot V_{s}+\dot V_{l}}{k} = \frac{1}{2}$

(ii) Only the small drain is opened

$\dot V_{s} = \frac{k}{t_{l}+3}$ (Eq. 3)

$\frac{\dot V_{s}}{k} = \frac{1}{t_{l}+3}$

(iii) Only the big drain is opened

$\dot V_{l} = \frac{k}{t_{l}}$ (Eq. 4)

$\frac{\dot V_{l}}{k} = \frac{1}{t_{l}}$

By applying (Eqs. 3, 4) in (Eq. 2) and making some algebraic handling, we find that:

$\frac{1}{t_{l}+3}+\frac{1}{t_{l}} = \frac{1}{2}$

$\frac{t_{l}+t_{l}+3}{t_{l}\cdot (t_{l}+3)} = \frac{1}{2}$

$2\cdot t_{l}+3 = t_{l}^{2}+3\cdot t_{l}$

$t_{l}^{2}-t_{l}-3 = 0$ (Eq. 5)

Whose roots are determined by the Quadratic Formula:

$t_{l,1}\approx 2.303\,h$ and $t_{l,2} \approx -1.302\,h$

Only the first roots offers a solution that is physically reasonable. Hence, the draining time when only the big drain is opened is 2.303 hours. And the time needed for the small drain is calculated by the following formula:

$t_{s} = 2.303\,h+3\,h$

$t_{s} = 5.303\,h$

The draining time when only the small drain is opened is 5.303 hours.

7 0

3 years ago

surface area of a cylinder with a radius of 8 centimeters and height of 10 centimeters? express the answer in hundredths.￼￼

surface area of a cylinder with a radius of 8 centimeters and height of 10 centimeters? express the answer in hundredths.