First term = 2(1) - 3 = 2 - 3 = -1
Answer:
I think its B
Step-by-step explanation:
Hope this helps:)
Answer:
a) No. t < 0 is not part of the useful domain of the function
b) 2.0 seconds
Step-by-step explanation:
a) A graph of the function is shown below. It shows t-intercepts at t=-0.25 and t=2.0. We presume that t is measured forward from some event such as the ball being thrown or hit. The model's predicted ball location has no meaning prior to that event, when values of t are negative.
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b) It is convenient to use a graphing calculator to find the t-intercepts. Or, the equation can be solved for h=0 any of several ways algebraically. One is by factoring.
h = 0 = -16t² +28t +8 . . . . . . . . . . . . the ball hits the ground when h = 0
0 = -4(4t² -7t -2) = -4(4t +1)(t -2)
This has t-intercepts where the factors are zero, at t=-1/4 and t=2.
The ball will hit the ground after 2 seconds.
X/6 >= 9
x >= 6 x 9
x >= 54
Therefore, 60, 72 and 54 satisfies the inequality.
Answer:
v1 = 1
Step-by-step explanation:
Solve for v1:
3 v1 - 3 = 0
Add 3 to both sides:
3 v1 + (3 - 3) = 3
3 - 3 = 0:
3 v1 = 3
Divide both sides of 3 v1 = 3 by 3:
(3 v1)/3 = 3/3
3/3 = 1:
v1 = 3/3
3/3 = 1:
Answer: v1 = 1