The speed of wind and plane are 105 kmph and 15 kmph respectively.
<u>Solution:</u>
Given, it takes 6 hours for a plane to travel 720 km with a tail wind and 8 hours to make the return trip with a head wind.
We have to find the air speed of the plane and speed of the wind.
Now, let the speed wind be "a" and speed of aeroplane be "b"
And, we know that, distance = speed x time.

Now at head wind → 
So, solve (1) and (2) by addition
2a = 210
a = 105
substitute a value in (1) ⇒ 105 + b = 120
⇒ b = 120 – 105 ⇒ b = 15.
Here, relative speed of plane during tail wind is 120 kmph and during head wind is 90 kmph.
Hence, speed of wind and plane are 105 kmph and 15 kmph respectively.
After 1 hour he has driven 40 miles
<h3>Hm ok, so the correct answer here would be (0,3) and heres why:</h3>
If the y would be equal to 0, everything would then just depend if you add or subtract the x:

Now the first answer could be correct for:

However, this answer is not correct for the other equation. the same true for all the other answers except (0,3)
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Answer:
1 2⋅−1⋅3 5=4 5
Step-by-step explanation:
Combine multiplied terms into a single fraction
12y−1⋅35=45
\frac{1}{2}y-1 \cdot \frac{3}{5}=\frac{4}{5}
21y−1⋅53=54
12−1⋅35=45
37.5% = 3/8 as a fraction.
So 180 x 8/3 would get you your answer.
Solution: 480