3 years ago

71(2)+68=. I am so so so bored, please let's talk

Mathematics

2 answers:

Zina [86]3 years ago

5 0

Answer:

210 and hiiiiii

Step-by-step explanation:

Vsevolod [243]3 years ago

5 0

Answer:

Yeah ok sure no prob

Step-by-step explanation:

So what's up

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Answer:

Therefore the solutions are

$x=0\\and\\ y =5\\\\Or\\\\x=-4\\and\\y=-3$

Step-by-step explanation:

Given:

$x^{2} + y^{2} =25$ .........( 1 )

$y-2x = 5\\y=2x+5$ ................( 2 )

To Find:

x = ?

y = ?

Solution:

Substituting ' y ' in Equation 1 we get

$x^{2}+(2x+5)^{2} =25$

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$x^{2}+4x^{2}+20x+25=25\\\\5x^{2}+20x=0\\5x(x+4)=0\\5x=0\ or\ x+4=0\\x=0\ or\ x= -4$

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$y=2\times 0+5=5$

Now Substitute x =-4 in equation 2 we get

$y=2\times -4+5=-3$

Therefore the solutions are

$x=0\\and\\ y =5\\\\Or\\\\x=-4\\and\\y=-3$

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71(2)+68=. I am so so so bored, please let's talk​

71(2)+68=. I am so so so bored, please let's talk