100y+x=230
150y+x=320
Y being the price per kilogram of steel bar, x being the added delivery fee.
If you were to solve the equaltion it would go x=230-100y by changing the first equation around the replacing that for the x int he second group, so you would get 150y+230-100y=320 or 50y=90 So Y=9/5dollars per kilogram. Or $1.8per kilogram, the delivery fee being $50
Answer:
The prove is as given below
Step-by-step explanation:
Suppose there are only finitely many primes of the form 4k + 3, say {p1, . . . , pk}. Let P denote their product.
Suppose k is even. Then P ≅ 3^k (mod 4) = 9^k/2 (mod 4) = 1 (mod 4).
ThenP + 2 ≅3 (mod 4), has to have a prime factor of the form 4k + 3. But pₓ≠P + 2 for all 1 ≤ i ≤ k as pₓ| P and pₓ≠2. This is a contradiction.
Suppose k is odd. Then P ≅ 3^k (mod 4) = 9^k/2 (mod 4) = 1 (mod 4).
Then P + 4 ≅3 (mod 4), has to have a prime factor of the form 4k + 3. But pₓ≠P + 4 for all 1 ≤ i ≤ k as pₓ| P and pₓ≠4. This is a contradiction.
So this indicates that there are infinite prime numbers of the form 4k+3.
Answer:
So there are 35 quarters and 21 nickels.
Step-by-step explanation:
So I guess that is all we have is quarters and nickels.
Quarters are worth .25
Nickels are worth .05
Let x represent the number of quarters
Let y represent the number of nickels
x+y=56
.25x+.05y=9.8
We are going to solve this system.
I'm going to use substitution. I will solve the first equation for y and then plug that into the second equation.
y=56-x
.25x+.05(56-x)=9.8
.25x+2.8-.05x=9.8
.20x+2.8=9.8
.2x = 7
x=7/(.2) or 7*5=35
y=56-x
y=56-35=21
So there are 35 quarters and 21 nickels.
Answer: 75.4 =
70
+ 5
+ 0.4
Step-by-step explanation:
Hope this helps :)
there is four lines of symmetry and yes angles ABC and DEF are ridget motion. the ridget moition is four units to the left and three units down. I hope this helps!!!
